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Pre-Calculas question, see comments for problem.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Solve for "x" \[\log_{3}((x-1)^{2})-2\log_{3}(3x-1)=1 \] I am quite rusty on my log's, and am a little unsure of how to go about solving this.
start with \[\log_3(\frac{(x-1)^2}{(3x-1)^2})=1\] then write in equivalent exponential form
\[\left (\frac{x-1}{3x-1} \right) ^2=3\]

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after that you are on your own, because that does not seem trivial to solve
well maybe. take the square root, then multiply out etc
Thank you very much. You've been very helpful.

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