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anonymous

  • 5 years ago

descartes rule of sigs to determine the possible number of positive and negative real zeros for each giving function. f(x)= x^3 +2x^2 + 5x + 4

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  1. anonymous
    • 5 years ago
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    but in this one we dont have to use synthetic devision

  2. anonymous
    • 5 years ago
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    but you need to know one soloution to use synthetic division

  3. anonymous
    • 5 years ago
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    When I was in highschool, we would graph it in calculator then use it to find other solution using synthetic division

  4. anonymous
    • 5 years ago
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    2X^4 -5x^3-x^2 - 6x+4 it has two sign changes and my teacher told me to divide it by and even number so what next im stuck at 2 and 1

  5. anonymous
    • 5 years ago
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    are you sure your function is right because solution are irrational http://www.wolframalpha.com/input/?i=2%28x%29%5E4-5%28x%29%5E3-%28x%29%5E2-6%28x%29%2B4

  6. anonymous
    • 5 years ago
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    thats what i have in my book for sure \[2X^4 -5x^3-x^2 - 6x+4\]

  7. anonymous
    • 5 years ago
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    and what does it what you to do?

  8. anonymous
    • 5 years ago
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    descartes rule of signs to determine the possible number of positive and negative real zeros for each giving function.

  9. anonymous
    • 5 years ago
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    there are 2 sign changes in your function which mean , you have 2 solution or an even number lower -- O solution .

  10. anonymous
    • 5 years ago
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    as my answer i wrote there are 2 solutions which are 2 and 1

  11. anonymous
    • 5 years ago
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    2x^4−5x^3−x^2−6x+4 this is how to do this: there are two sign changes which mean, there are two or 0(even number lower) positive solution. to find negative soloution, invert the sign of the term with odd power 2x^4+5x^3 - x^2 + 6 x+4 which mean it has either 2 or 0 solution negative solution

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