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anonymous
 5 years ago
descartes rule of sigs to determine the possible number of positive and negative real zeros for each giving function.
f(x)= x^3 +2x^2 + 5x + 4
anonymous
 5 years ago
descartes rule of sigs to determine the possible number of positive and negative real zeros for each giving function. f(x)= x^3 +2x^2 + 5x + 4

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but in this one we dont have to use synthetic devision

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but you need to know one soloution to use synthetic division

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0When I was in highschool, we would graph it in calculator then use it to find other solution using synthetic division

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02X^4 5x^3x^2  6x+4 it has two sign changes and my teacher told me to divide it by and even number so what next im stuck at 2 and 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you sure your function is right because solution are irrational http://www.wolframalpha.com/input/?i=2%28x%29%5E45%28x%29%5E3%28x%29%5E26%28x%29%2B4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats what i have in my book for sure \[2X^4 5x^3x^2  6x+4\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and what does it what you to do?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0descartes rule of signs to determine the possible number of positive and negative real zeros for each giving function.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there are 2 sign changes in your function which mean , you have 2 solution or an even number lower  O solution .

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0as my answer i wrote there are 2 solutions which are 2 and 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02x^4−5x^3−x^2−6x+4 this is how to do this: there are two sign changes which mean, there are two or 0(even number lower) positive solution. to find negative soloution, invert the sign of the term with odd power 2x^4+5x^3  x^2 + 6 x+4 which mean it has either 2 or 0 solution negative solution
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