descartes rule of sigs to determine the possible number of positive and negative real zeros for each giving function.
f(x)= x^3 +2x^2 + 5x + 4
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but in this one we dont have to use synthetic devision
but you need to know one soloution to use synthetic division
When I was in highschool, we would graph it in calculator then use it to find other solution using synthetic division
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2X^4 -5x^3-x^2 - 6x+4 it has two sign changes and my teacher told me to divide it by and even number
so what next im stuck at 2 and 1
are you sure your function is right because solution are irrational
thats what i have in my book
\[2X^4 -5x^3-x^2 - 6x+4\]
and what does it what you to do?
descartes rule of signs to determine the possible number of positive and negative real zeros for each giving function.
there are 2 sign changes in your function which mean , you have 2 solution or an even number lower -- O solution .
as my answer i wrote there are 2 solutions which are 2 and 1
this is how to do this:
there are two sign changes which mean, there are two or 0(even number lower) positive solution.
to find negative soloution, invert the sign of the term with odd power
2x^4+5x^3 - x^2 + 6 x+4
which mean it has either 2 or 0 solution negative solution