The number of protons and neutrons in the nucleus of an atom must always be equal, in order for the strong nuclear force binding them together to be effective. True or false?
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
grab a periodic table and look at the average mass of carbon: ~12, so 6protons, 6 neutrons. Now look at the average mass of gold and tell me true or false.
Alright, doing that now!
Well I know that the mass of carbon-12 is smaller than the mass of gold. I don't think that the protons and neutrons in gold are equal though, I could be wrong.
Not the answer you are looking for? Search for more explanations.
it's not the mass of the 2 atoms that's important here. It's the number of protons and neutrons that they each have.
Carbon's average mass is ~12, so 6 protons and 6 neutrons.
Gold's average mass is ~197, but only has 79 protons. The remaining mass comes from 118 neutrons. 79 and 118 are definitely not equal.
Most atoms with fewer than 20 protons also tend to have the same # of neutrons. As the atoms get more and more protons, the number of neutrons increases even faster, so the A/Z ratio (mass/protons) gets larger and larger in order for atoms to be stable.