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SamIam

  • 5 years ago

Solve the matrix equation for A?

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  1. SAMIAM
    • 5 years ago
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    |dw:1327007851191:dw|

  2. SAMIAM
    • 5 years ago
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    Oh yay my friends are here

  3. TuringTest
    • 5 years ago
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    you need the inverse of the matrix on the left, do you know how to find that?

  4. SAMIAM
    • 5 years ago
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    I know how to do that but they want me to do a simpler method

  5. TuringTest
    • 5 years ago
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    ...like what? maybe it would help if I could actually see the matrix on the right. try to use the equation feature to type it, you can make 2X2 matrices with it.

  6. SAMIAM
    • 5 years ago
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    |dw:1327008078673:dw|

  7. TuringTest
    • 5 years ago
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    is the right side the identity matrix?

  8. SAMIAM
    • 5 years ago
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    ya but we didnt really learn that yet. We only learnt multiplying and addition and subtraction

  9. TuringTest
    • 5 years ago
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    I can't see the matrix on the RHS is my problem what is it, the identity matrix?

  10. SAMIAM
    • 5 years ago
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    Like maybe a is a 2 by 2 matrix

  11. SAMIAM
    • 5 years ago
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    ohhh i see it okk i will redraw it

  12. SAMIAM
    • 5 years ago
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    |dw:1327008221822:dw|

  13. amistre64
    • 5 years ago
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    since BA=I wouldnt A=B^-1 I ?

  14. SAMIAM
    • 5 years ago
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    I know but we didnt really use inverse matrices yet But if i cant solve it any other way i will do it that way

  15. TuringTest
    • 5 years ago
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    ...so that is the identity matrix so we could solve this by multiplying out our matrix A with the one on the LHS and get a system of equations:\[2a_{11}-a_{21}=1\]\[3a_{11}-2a_{21}=0\]\[2a_{12}-a_{22}=0\]\[3a_{12}-2a_{22}=1\]

  16. amistre64
    • 5 years ago
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    \[\begin{pmatrix}a&b\\c&d\end{pmatrix}^{-1}=\frac{1}{det}\begin{pmatrix}d&-b\\-c&a\end{pmatrix}\]

  17. TuringTest
    • 5 years ago
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    I only did it this way amistre because they said not to use the inverse... but yes, the inverse seems the smarter/easier way to do it.

  18. amistre64
    • 5 years ago
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    youre way is fine, I just did that for the practice really :)

  19. SAMIAM
    • 5 years ago
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    ok Thanks

  20. amistre64
    • 5 years ago
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    also, i think the GaussJordan comes up with an inverse as well

  21. SAMIAM
    • 5 years ago
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    Ya it does :D Thanks guys

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