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anonymous

  • 5 years ago

erin and susan both took their dogs for a walk. Together theyw alked 15 miles. If erin walked 3 miles less than susan how far did susan walk with her dog?

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  1. Mertsj
    • 5 years ago
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    e=s-3 e+s=15 Replace e in the second equation wis s-3 from the first equation and solve.

  2. anonymous
    • 5 years ago
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    Let distance covered by susan = x miles then distance covered by erin = (x - 3) miles together they walked 15 miles menas x + (x - 3) = 15 2x - 3 = 15 2x = 15 + 3 x = 18/2 x = 9 so susan walked 9 miles and erin walked (9-3) = 6 miles

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