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anonymous
 5 years ago
how do i solve these kinds of problems?
x 3/2 = 64
anonymous
 5 years ago
how do i solve these kinds of problems? x 3/2 = 64

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0on my paper it looks like x with exponent 3 and exponent 2 = 64.... not sure how to put that on here

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.0\[x^{\frac{3}{2}}=64\]is that right?

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.0ok, firstly note that \(x^{\frac{1}{2}}\) means square root of x

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.0so if we square both sides we get:\[(x^{\frac{3}{2}})^2=64^2\]therefore:\[x^3=64^2\]

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.0so we can write this as:\[x^3=64^2=(2^6)^2=2^{12}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait i got confused, let me look at what you put

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.0I am using the rule:\[(x^a)^b=x^{ab}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why is 64 squared 2 to 6th and not just 8?

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.0\[64=2^6\]therefore:\[64^2=(2^6)^2=2^{12}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no. 'im still trying to understand the squared part

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.0ok, you agree:\[64=2^6\]

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.0so we can substitute \(2^6\) where ever we see 64. so we can write:\[64^2=(64)^2=(2^6)^2=2^{12}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i mean i understand the substituting part but i still dont understand the 64 squared = 2 to the 12th

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.0are you familiar with the rule:\[(x^a)^b=x^{ab}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but i just learned it, not a pro yet

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.0ok, lets try a different approach...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, im sorry and thank you for being patient with me

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.0\[64=2^6\]so we can write:\[64^p=(64)^p=(2^6)^p=2^{6p}\]

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.0we could also have written it as:\[64=8^2\]therefore:\[64^2=(8^2)^2=8^4\]

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.0and then used:\[8=2^3\]therefore:\[64^2=8^4=(8)^4=(2^3)^4=2^{12}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0aha, and 8 to the 4th is the same as 2 to the 12th....ok got it now

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.0yes  well done  I think the fog is beginning to clear :)

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.0ok, so lets review our last step...

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.0we got to:\[x^3=64^2=(2^6)^2=2^{12}\]this should now be clear  yes?

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.0ok, so next we take cube roots of both sides to get:\[(x^3)^{\frac{1}{3}}=(2^{12})^{\frac{1}{3}}\]therefore:\[x=2^4=16\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, i was doing the calculating to follow along with you

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.0no problem  the main thing is to ensure you understand the concepts

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes well you explained it great, thanks

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.0you are very welcome. is it all clear now or did you want more explanation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think i got it now, i was just stuck on the squared part. makes sense now. Thank you very much

asnaseer
 5 years ago
Best ResponseYou've already chosen the best response.0ok  I'm glad I was enable to assist you in your mathematical quest :p  all the best...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0gotcha... thanks again :)
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