A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
how do i solve these kinds of problems?
x 3/2 = 64
anonymous
 4 years ago
how do i solve these kinds of problems? x 3/2 = 64

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0on my paper it looks like x with exponent 3 and exponent 2 = 64.... not sure how to put that on here

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0\[x^{\frac{3}{2}}=64\]is that right?

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0ok, firstly note that \(x^{\frac{1}{2}}\) means square root of x

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0so if we square both sides we get:\[(x^{\frac{3}{2}})^2=64^2\]therefore:\[x^3=64^2\]

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0so we can write this as:\[x^3=64^2=(2^6)^2=2^{12}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait i got confused, let me look at what you put

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0I am using the rule:\[(x^a)^b=x^{ab}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0why is 64 squared 2 to 6th and not just 8?

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0\[64=2^6\]therefore:\[64^2=(2^6)^2=2^{12}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no. 'im still trying to understand the squared part

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0ok, you agree:\[64=2^6\]

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0so we can substitute \(2^6\) where ever we see 64. so we can write:\[64^2=(64)^2=(2^6)^2=2^{12}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i mean i understand the substituting part but i still dont understand the 64 squared = 2 to the 12th

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0are you familiar with the rule:\[(x^a)^b=x^{ab}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but i just learned it, not a pro yet

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0ok, lets try a different approach...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok, im sorry and thank you for being patient with me

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0\[64=2^6\]so we can write:\[64^p=(64)^p=(2^6)^p=2^{6p}\]

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0we could also have written it as:\[64=8^2\]therefore:\[64^2=(8^2)^2=8^4\]

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0and then used:\[8=2^3\]therefore:\[64^2=8^4=(8)^4=(2^3)^4=2^{12}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0aha, and 8 to the 4th is the same as 2 to the 12th....ok got it now

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0yes  well done  I think the fog is beginning to clear :)

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0ok, so lets review our last step...

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0we got to:\[x^3=64^2=(2^6)^2=2^{12}\]this should now be clear  yes?

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0ok, so next we take cube roots of both sides to get:\[(x^3)^{\frac{1}{3}}=(2^{12})^{\frac{1}{3}}\]therefore:\[x=2^4=16\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok, i was doing the calculating to follow along with you

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0no problem  the main thing is to ensure you understand the concepts

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes well you explained it great, thanks

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0you are very welcome. is it all clear now or did you want more explanation?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think i got it now, i was just stuck on the squared part. makes sense now. Thank you very much

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0ok  I'm glad I was enable to assist you in your mathematical quest :p  all the best...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0gotcha... thanks again :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.