anonymous
  • anonymous
18m^2-1 factor plz!
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[81m^2-1\]
anonymous
  • anonymous
wait which one, or both
anonymous
  • anonymous
both plz!

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
if you set them to zero just have 18m^2 -1=0 18m^2 =1 m^2 = 1/18 \[m = \sqrt{1/18}\]
anonymous
  • anonymous
so the same with the other you will have \[(m - \sqrt{1/18})^{2}\] and \[(m - \sqrt{1/81})^{2}\]
anonymous
  • anonymous
THANKZ YOUZ!
anonymous
  • anonymous
your welcome
asnaseer
  • asnaseer
@Davidjohn - I /think/ your last steps where you factorized the expressions has a mistake in it. I believe you can use the rule \(a^2-b^2=(a+b)(a-b)\) to get:\[81m^2-1=9^2m^2-1^2=(9m)^2-1^2=(9m+1)(9m-1)\]
anonymous
  • anonymous
@asnaseer that makes a whole lot more sense!
anonymous
  • anonymous
oh yeah, i generalized that one too much, youre right
anonymous
  • anonymous
but the answer would be right if expanded because it would simplify down and you could multiply them to get the same answer
asnaseer
  • asnaseer
glad I could help - and no worries @Davidjohn - we all make mistakes - that's what makes us human :-)
anonymous
  • anonymous
ah except it would be plus or minus then, not just minus minus
asnaseer
  • asnaseer
\[(m - \sqrt{1/81})^{2}=m^2-2\sqrt{1/81}+1/81\]
anonymous
  • anonymous
right my bad :) thanks for correcting
anonymous
  • anonymous
Woah... the first thing you showed me was a lot easier to understand...
asnaseer
  • asnaseer
:)

Looking for something else?

Not the answer you are looking for? Search for more explanations.