## anonymous 4 years ago What is the range of the graph of y = –3(x – 2)^2 + 3?

1. anonymous

$f(x) \leq 3$ Reason? The quantity $(x-2)^2\geq 0$ for all $x \in \mathbb{R}.$ Hence $-3(x-2)^2 \leq 0$ Therefore $f(x) = -3(x-2)^2 + 3 \leq 3$

2. anonymous

So a nice subsequent question is: For what value of $x$ does $f(x)$ take it's largest value 3?