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anonymous

  • 5 years ago

8m-16 ÷ 3m-6 -20 40

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  1. asnaseer
    • 5 years ago
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    I am not sure I understand you question - can you please clarify?

  2. asnaseer
    • 5 years ago
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    is this:\[(8m-16)\div(3m-6)\]with two choices for the answer: -20 or 40?

  3. anonymous
    • 5 years ago
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    no the 20 should have a line above it but under the 8m-16 and the same with the 40 and 3m-16

  4. asnaseer
    • 5 years ago
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    ok, so question is:\[\frac{8m-16}{20}\div\frac{3m-6}{40}\]correct?

  5. anonymous
    • 5 years ago
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    yes it wouldnt let me type it like that but thats correct

  6. asnaseer
    • 5 years ago
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    ok, do you the rule for dividing fractions? i.e. this rule:\[\frac{a}{b}\div\frac{p}{q}=\frac{a}{b}\times\frac{q}{p}\]

  7. asnaseer
    • 5 years ago
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    *do you know the rule...

  8. anonymous
    • 5 years ago
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    yes

  9. asnaseer
    • 5 years ago
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    so we can make use of this to get:\[\frac{8m-16}{20}\div\frac{3m-6}{40}=\frac{8m-16}{20}\times\frac{40}{3m-6}\]

  10. asnaseer
    • 5 years ago
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    you can also factorise a bit to get:\[\frac{8m-16}{20}\times\frac{40}{3m-6}=\frac{8(m-2)}{20}\times\frac{40}{3(m-2)}\]

  11. asnaseer
    • 5 years ago
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    you now be able to cancel some things out. are you able to work it out yourself from here?

  12. anonymous
    • 5 years ago
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    ok once i cancel out the m-2 i get lost

  13. anonymous
    • 5 years ago
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    bec ause the 20 is negative

  14. asnaseer
    • 5 years ago
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    ok, let me show you the steps...

  15. asnaseer
    • 5 years ago
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    oh - so the equation I wrote was not correct?

  16. anonymous
    • 5 years ago
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    im sorry i thought u put a -20

  17. asnaseer
    • 5 years ago
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    are you saying it should be:\[\frac{8(m-2)}{-20}\times\frac{40}{3(m-2)}\]

  18. anonymous
    • 5 years ago
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    yes

  19. asnaseer
    • 5 years ago
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    ok , I'll try and illustrate the steps to you...

  20. asnaseer
    • 5 years ago
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    |dw:1327017741147:dw|

  21. asnaseer
    • 5 years ago
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    |dw:1327017793288:dw|

  22. asnaseer
    • 5 years ago
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    |dw:1327017851696:dw|

  23. anonymous
    • 5 years ago
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    omg thanks so much..... i just have one more problem that im stuck on

  24. asnaseer
    • 5 years ago
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    so you end up with:\[\frac{8}{-1}\times\frac{2}{3}=\frac{16}{-3}=-\frac{16}{3}=-5\frac{1}{3}\]

  25. asnaseer
    • 5 years ago
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    just post your new question to the left and I'm sure there will be lots of people willing to help. unfortunately I need to leave now otherwise I would have assisted you.

  26. anonymous
    • 5 years ago
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    thanks though

  27. asnaseer
    • 5 years ago
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    yw

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