8m-16 ÷ 3m-6 -20 40

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8m-16 ÷ 3m-6 -20 40

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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I am not sure I understand you question - can you please clarify?
is this:\[(8m-16)\div(3m-6)\]with two choices for the answer: -20 or 40?
no the 20 should have a line above it but under the 8m-16 and the same with the 40 and 3m-16

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ok, so question is:\[\frac{8m-16}{20}\div\frac{3m-6}{40}\]correct?
yes it wouldnt let me type it like that but thats correct
ok, do you the rule for dividing fractions? i.e. this rule:\[\frac{a}{b}\div\frac{p}{q}=\frac{a}{b}\times\frac{q}{p}\]
*do you know the rule...
yes
so we can make use of this to get:\[\frac{8m-16}{20}\div\frac{3m-6}{40}=\frac{8m-16}{20}\times\frac{40}{3m-6}\]
you can also factorise a bit to get:\[\frac{8m-16}{20}\times\frac{40}{3m-6}=\frac{8(m-2)}{20}\times\frac{40}{3(m-2)}\]
you now be able to cancel some things out. are you able to work it out yourself from here?
ok once i cancel out the m-2 i get lost
bec ause the 20 is negative
ok, let me show you the steps...
oh - so the equation I wrote was not correct?
im sorry i thought u put a -20
are you saying it should be:\[\frac{8(m-2)}{-20}\times\frac{40}{3(m-2)}\]
yes
ok , I'll try and illustrate the steps to you...
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omg thanks so much..... i just have one more problem that im stuck on
so you end up with:\[\frac{8}{-1}\times\frac{2}{3}=\frac{16}{-3}=-\frac{16}{3}=-5\frac{1}{3}\]
just post your new question to the left and I'm sure there will be lots of people willing to help. unfortunately I need to leave now otherwise I would have assisted you.
thanks though
yw

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