A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 4 years ago

Calculus III: Find the center, foci, vertices, and eccentricty of the ellipse, and sketch its graph. (x+4)^2+(y+6)^2 -------- = 1 1/4

  • This Question is Closed
  1. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Give me a second to re post this problem...

  2. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[(x+4)^{2}+(y+6)^{2} = 1\] I don't know how to make a fraction using this code, but there is suppose to be a 1/4 underneath the (y+6)^2.

  3. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I don't know why its not posting up my equation in the proper form but anyways my problem with this particular problem is identifying "a" and "b". Would I have to flip the "1/4" first and then "a" and "b" would be 1?

  4. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.