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anonymous

  • 5 years ago

write x^2 - 9 / x (x^3 - 4x / x^2 +5x +6) in simplest form.

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  1. myininaya
    • 5 years ago
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    \[\frac{x^2-9}{x} \frac{x^3-4x}{x^2+5x+6}\] is that the question?

  2. anonymous
    • 5 years ago
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    yeah pretty much. because the question is asking to find the area of the rectangle. |dw:1327020602568:dw|

  3. anonymous
    • 5 years ago
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    in simplest form

  4. myininaya
    • 5 years ago
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    have you factor all four of those polynomials?

  5. anonymous
    • 5 years ago
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    ohs. yeah that's what i was doing. but i keep getting and doing it wrong

  6. myininaya
    • 5 years ago
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    \[\frac{(x-3)(x+3)}{x} \frac{x(x^2-4)}{(x+2)(x+3)}\]

  7. myininaya
    • 5 years ago
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    did you get that far?

  8. anonymous
    • 5 years ago
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    yeah i got to that part.

  9. myininaya
    • 5 years ago
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    ok also x^2-4 is factorable

  10. myininaya
    • 5 years ago
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    \[\frac{(x-3)(x+3)}{x} \frac{x(x-2)(x+2)}{(x+2)(x+3)}\]

  11. anonymous
    • 5 years ago
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    ohhh ! okay i didn't do that part.

  12. myininaya
    • 5 years ago
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    now you have somethings to cancel, right?

  13. anonymous
    • 5 years ago
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    yep (x+3) and the (x+2) and the x ?

  14. myininaya
    • 5 years ago
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    \[\frac{(x-3) \not{(x+3)} }{ \not{x}} \frac{ \not{x} (x-2) \not{(x+2)}}{\not{(x+2)} \not{(x+3)}}\]

  15. myininaya
    • 5 years ago
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    i couldn't get the lines to go over the whole part

  16. myininaya
    • 5 years ago
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    so you have (x-3)(x-2) left right?

  17. anonymous
    • 5 years ago
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    yep so then the answer would be x^2- 5x +6

  18. anonymous
    • 5 years ago
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    OHHHH ! now i get it :) thank you !

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