Let f(x)={4x−1, if x≤3...... .............−5x+b, if x>3 If f(x) is a function which is continuous everywhere, then we must have b=

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Let f(x)={4x−1, if x≤3...... .............−5x+b, if x>3 If f(x) is a function which is continuous everywhere, then we must have b=

Mathematics
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do the left limit and right limit for x=3 and set them equal and solve for b
ohh i see
how would i go about solving this one...same way? For what value of the constant c is the function f continuous on (−∞,∞) where f(x)=...... cx+8 if x∈(−∞,2] ....... cx^2−8 if x∈(2,∞)......

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yes you look at the left limit and right limit for x=2
and set them equal
hey so for the first problem...i used 4(3)-1 = 11 and -5(3.1)+b = -15.5 + b. So I set -15.5 + b = 11 and I did the algebra and ended up with -4.5. what did i do wrong?
\[4(3)-1=-5(3)+b\]
yeah shouldnt u get a -4.5 after you do the algebra
i don't know i can perform the operations if you want me too
4(3)=12 12-1=11 -5(3)=-15 so we have 11=-15+b By adding 15 on both sides we get 26=b
oh snap i did it backward haha thanks
can i use 1.5 and 3 for the second question
i don't understand
how would i go about solving this one...same way? For what value of the constant c is the function f continuous on (−∞,∞) where f(x)=...... cx+8 if x∈(−∞,2] ....... cx^2−8 if x∈(2,∞)...... once again i have to approach from both sides...if im approaching from left can I use x=1.5 and right x=3?
what no just before we plugged in 3 for both sides here we do 2
\[c(2)+8=c(2)^2-8\]
now solve for c

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