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anonymous
 4 years ago
how do you simplify squaring square roots?
anonymous
 4 years ago
how do you simplify squaring square roots?

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TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.0um... like\[(\sqrt{x})^2\]?? Example please

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well the first number is \[\sqrt{?}\]14

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0replace the ? with 14

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the square root of 14 is 3.7. so no you cannot because it is a decimal

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so what would you put down as your answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0for that specific question i would put no. but it would work for instance, the squareroot of 16, which is 4, and the squareroot of 4 is 2. it varies from which number you are finding the square root for

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.0In general you should try to factor the number under the root sign. \[\sqrt{14}=\sqrt{7\times 2}\]so this cannot be simplified. If however you had\[\sqrt{16}=\sqrt{2\times2\times2\times2}\]you can 'pull out' one copy of any number you have two copies of. In this case we have four 2's, so we can pull two 2's out of the sign and multiply them together:\[\sqrt{16}=\sqrt{2\times2\times2\times2}=2\times2=4\]A couple more examples for the sake of clarity:\[\sqrt{8}=\sqrt{2\times2\times2}=2\sqrt2\]\[\sqrt{108}=\sqrt{2\times2\times3\times3\times3}=(2\times3)\sqrt3=6\sqrt3\]
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