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anonymous
 4 years ago
solve the polynomial equation hhhhheeeeellllpppppppppp!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
x^33x+2=0
6x^311x^2+6x1=0
(2x+1)(3x2)^3(2x7)=0
2x^3+5x^2200x500=0
x^4x^311x^2=x+12
anonymous
 4 years ago
solve the polynomial equation hhhhheeeeellllpppppppppp!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! x^33x+2=0 6x^311x^2+6x1=0 (2x+1)(3x2)^3(2x7)=0 2x^3+5x^2200x500=0 x^4x^311x^2=x+12

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Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0You know, this is too much for one question. But let's tackle the first one.

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0The possible rational roots of the first equation are +1, +2. Let's use synthetic division to see if any of these possible roots are actually roots.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0With a little help from Mathematica: \[\left\{2 x^3+5 x^2200 x500=0,(x10) (x+10) (2 x+5)=0\right\}\left\{x^4x^311 x^2=x+12,(x4) (x+3) \left(x^2+1\right)=0\right\} \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thnks guys i still need a bit more help
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