solve the polynomial equation hhhhheeeeellllpppppppppp!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! x^3-3x+2=0 6x^3-11x^2+6x-1=0 (2x+1)(3x-2)^3(2x-7)=0 2x^3+5x^2-200x-500=0 x^4-x^3-11x^2=x+12

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solve the polynomial equation hhhhheeeeellllpppppppppp!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! x^3-3x+2=0 6x^3-11x^2+6x-1=0 (2x+1)(3x-2)^3(2x-7)=0 2x^3+5x^2-200x-500=0 x^4-x^3-11x^2=x+12

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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You know, this is too much for one question. But let's tackle the first one.
The possible rational roots of the first equation are +-1, +-2. Let's use synthetic division to see if any of these possible roots are actually roots.
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With a little help from Mathematica: \[\left\{2 x^3+5 x^2-200 x-500=0,(x-10) (x+10) (2 x+5)=0\right\}\left\{x^4-x^3-11 x^2=x+12,(x-4) (x+3) \left(x^2+1\right)=0\right\} \]
thnks guys i still need a bit more help

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