## anonymous 4 years ago solve the polynomial equation hhhhheeeeellllpppppppppp!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! x^3-3x+2=0 6x^3-11x^2+6x-1=0 (2x+1)(3x-2)^3(2x-7)=0 2x^3+5x^2-200x-500=0 x^4-x^3-11x^2=x+12

1. Mertsj

You know, this is too much for one question. But let's tackle the first one.

2. Mertsj

The possible rational roots of the first equation are +-1, +-2. Let's use synthetic division to see if any of these possible roots are actually roots.

3. Mertsj

|dw:1327027178615:dw|

4. anonymous

With a little help from Mathematica: $\left\{2 x^3+5 x^2-200 x-500=0,(x-10) (x+10) (2 x+5)=0\right\}\left\{x^4-x^3-11 x^2=x+12,(x-4) (x+3) \left(x^2+1\right)=0\right\}$

5. anonymous

thnks guys i still need a bit more help