anonymous
  • anonymous
If w = 3 in and h = 4 in, what is the surface area of the right square pyramid? *Note: Picture not drawn to scale.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
60 in2 111 in2 66 in2 96 in2 I was thinking C 66
anonymous
  • anonymous
Since you have been given w and h, you need to find a way to express s in terms of the other two known variables. This is the only way you will be able to get a numerical answer. The only trig relation you can make in this situation (since there are no angles) is to use the Pythagorean theorem. In this case, that would imply h^2 + w^2 = s^2 This implies that s = +/-sqrt(h^2 + w^2) But since we are dealing with distances and we don't care about the negative answer, we can simply say that s = sqrt(h^2 + w^2)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
so ?
anonymous
  • anonymous
Now, the surface area of the pyramid is going to be the sum of the area of the four triangles and the sum of the square base. The area of each triangle is going to be it's base times height which is Area of triangle = 2w*s = 2w*sqrt(h^2+w^2) And obviously, the square part is going to be Area of square = (2w)^2 = 4w^2 So, all you have to do is plug in the values.
anonymous
  • anonymous
so would it be C
anonymous
  • anonymous
do its D got it :D
anonymous
  • anonymous
Yeah it is D. My triangle area should be ws not 2ws, but I'm sure you figured that out.

Looking for something else?

Not the answer you are looking for? Search for more explanations.