IsTim
  • IsTim
Graph the function:y=3csc[1/2(x-3pi/4)]+5. State the domain and range.
Mathematics
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

IsTim
  • IsTim
Just wondering, would I graph the function y=sinx, and then apply the transformations from teh function onto that? Once I'm done that, would I then continue on with how I would usually graph y=cscx?
Akshay_Budhkar
  • Akshay_Budhkar
the only place the function is not defined is when cosec x is infinity or sinx is 0
Akshay_Budhkar
  • Akshay_Budhkar
so u can get the domain

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Akshay_Budhkar
  • Akshay_Budhkar
also cosec x ranges from -∞ to ∞ . so this function has a range as all real numbers
IsTim
  • IsTim
I'm worried about graphing it though.
Akshay_Budhkar
  • Akshay_Budhkar
oh
Akshay_Budhkar
  • Akshay_Budhkar
better graph cosecx first then the transformations
IsTim
  • IsTim
I'll figure out the domain and range once I get the graph. But what you said, I guess the Range is yEr.
IsTim
  • IsTim
Ok. Graph the original first?
IsTim
  • IsTim
Gimme me a minute. I guess you can do what you want while you're waiting.
IsTim
  • IsTim
done.
Akshay_Budhkar
  • Akshay_Budhkar
my medal
IsTim
  • IsTim
Lol. K.
Akshay_Budhkar
  • Akshay_Budhkar
:P
Akshay_Budhkar
  • Akshay_Budhkar
ok u fine man?
IsTim
  • IsTim
Not yet. I've got the base function, but I'm struggling with dem transformations.
IsTim
  • IsTim
My solution sounds wrong to me though.
Akshay_Budhkar
  • Akshay_Budhkar
try wolhphram and compare ur graph!
IsTim
  • IsTim
Link it?
Akshay_Budhkar
  • Akshay_Budhkar
i cant make it on this site :/
IsTim
  • IsTim
Gimme the link. I'll give it a a look.
IsTim
  • IsTim
Hello?
Akshay_Budhkar
  • Akshay_Budhkar
ok wait
Akshay_Budhkar
  • Akshay_Budhkar
i m helping 3 ppl and discussing a question with 3 others
Akshay_Budhkar
  • Akshay_Budhkar
so its diff
Akshay_Budhkar
  • Akshay_Budhkar
:P
IsTim
  • IsTim
Gotcha.
Akshay_Budhkar
  • Akshay_Budhkar
http://www.wolframalpha.com/input/?i=%3Ay%3D3csc%5B1%2F2%28x-3pi%2F4%29%5D%2B5
IsTim
  • IsTim
Thanks man.
Akshay_Budhkar
  • Akshay_Budhkar
anything for you :P
IsTim
  • IsTim
Great. Nice to know I've got support.
IsTim
  • IsTim
Wait. The x-line thing; could I changethat to radians/pi?
Akshay_Budhkar
  • Akshay_Budhkar
why?
IsTim
  • IsTim
It's how I learnt to do it. The teacher asks us to do it in radians too.
Akshay_Budhkar
  • Akshay_Budhkar
u can change it

Looking for something else?

Not the answer you are looking for? Search for more explanations.