A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
can anyone help me with integration
anonymous
 4 years ago
can anyone help me with integration

This Question is Closed

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0Quite a few people on to night are more than competent to help with your likely question. Post it.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327030921905:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Separate it into two integrals. Divide the sqrt(2) into the top and then you have 2 trivial integrals.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you show how you would do it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327031115564:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327031166888:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327031304975:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm not sure what you did there. How did you get a square root 2? That would just make it harder. Remember that since constants don't change with the variables, you can always pull them out of the integral. You can even do the following:

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327031471323:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{1}{\sqrt{2}}\int_1^4 (u2)du = \frac{1}{\sqrt{2}}\left(\frac12u^22u\right_1^4=\frac{3}{2\sqrt{2}}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats worng because my book says the answer is 2/3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Your book is incorrect. This answer is correct, with wolfram as additional evidence to boot: http://www.wolframalpha.com/input/?i=integrate+%28x2%29%2Fsqrt%282%29+from+1+to+4

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no i dont think so because iam using the fundemental thereom of calculus

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Does your question specifically ask to solve \[\int_1^4\frac{u2}{\sqrt{2}}du\] Because the answer to that is what I stated. If the problem in the text is different, let me know and we'll go from there.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats exactly how it reads and it asks to evaluate the definite integral

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Mhm, the answer is what I said.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Think of it this way, since u2 is a linear equation, you are just calculating the areas of a couple of triangles with rational side lengths. However, dividing by the square root of 2 (an irrational number) will necessitate that your integral is irrational. 2/3 is not irrational, so that cannot be the answer.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.