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anonymous
 5 years ago
I have a question about trigonometry. I will write out the question. Once I post the question, I will then post an "answer" but it'd just be a drawing of how the triangle looks in the problem.
Solve for x in the following right triangle, if a=53 and b=5.
anonymous
 5 years ago
I have a question about trigonometry. I will write out the question. Once I post the question, I will then post an "answer" but it'd just be a drawing of how the triangle looks in the problem. Solve for x in the following right triangle, if a=53 and b=5.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1327031826563:dw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hopefully that is readable. I tried drawing that with my laptop.

UnkleRhaukus
 5 years ago
Best ResponseYou've already chosen the best response.0well \[√a^2=x^2+(x+b)^2\]

UnkleRhaukus
 5 years ago
Best ResponseYou've already chosen the best response.0\[a=x^2+x^2+2bx+b^2\] \[a=2x^2+2bx+b^2\]

UnkleRhaukus
 5 years ago
Best ResponseYou've already chosen the best response.0triangles have positive side lengths

Mertsj
 5 years ago
Best ResponseYou've already chosen the best response.2reject 7 since length of line segment can't be negative

UnkleRhaukus
 5 years ago
Best ResponseYou've already chosen the best response.0that is a 2,7,√53 triangle

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So you're allowed to get the answer to equal 0, correct? (where you subtracted the 53 from the right side)

UnkleRhaukus
 5 years ago
Best ResponseYou've already chosen the best response.0which we know is correct because \[2^2+7^2=√53^2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So you're allowed to get the answer to equal 0, correct? (where you subtracted the 53 from the right side)
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