anonymous
  • anonymous
I have a question about trigonometry. I will write out the question. Once I post the question, I will then post an "answer" but it'd just be a drawing of how the triangle looks in the problem. Solve for x in the following right triangle, if a=53 and b=5.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
|dw:1327031826563:dw|
anonymous
  • anonymous
hopefully that is readable. I tried drawing that with my laptop.
UnkleRhaukus
  • UnkleRhaukus
well \[√a^2=x^2+(x+b)^2\]

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UnkleRhaukus
  • UnkleRhaukus
\[a=x^2+x^2+2bx+b^2\] \[a=2x^2+2bx+b^2\]
Mertsj
  • Mertsj
|dw:1327032036209:dw|
Mertsj
  • Mertsj
|dw:1327032236614:dw|
UnkleRhaukus
  • UnkleRhaukus
triangles have positive side lengths
Mertsj
  • Mertsj
reject -7 since length of line segment can't be negative
Mertsj
  • Mertsj
so the result is x = 2
UnkleRhaukus
  • UnkleRhaukus
that is a 2,7,√53 triangle
anonymous
  • anonymous
So you're allowed to get the answer to equal 0, correct? (where you subtracted the 53 from the right side)
UnkleRhaukus
  • UnkleRhaukus
which we know is correct because \[2^2+7^2=√53^2\]
anonymous
  • anonymous
So you're allowed to get the answer to equal 0, correct? (where you subtracted the 53 from the right side)

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