anonymous
  • anonymous
SIMPLIFY ~ (x^5)^-8x^4
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
\[(x^5)^{-8x^4}=x^{-40x^4}\]
anonymous
  • anonymous
\[(a^m)^n=a^{mn}\] ^---Rule
anonymous
  • anonymous
my opinions are fractions.

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anonymous
  • anonymous
\[\frac{1}{x^{40x^4}}\] Is this one of your options?
anonymous
  • anonymous
no i have 1 over x^160 or 1 over x^36 or x^-36 or i over x^12
anonymous
  • anonymous
was the question supposed to be \[(x^5)^{-8\times 4}\]?
anonymous
  • anonymous
If so then the answer is \[\frac{1}{x^{160}}\]
anonymous
  • anonymous
|dw:1327037411441:dw|
anonymous
  • anonymous
HELP~
anonymous
  • anonymous
\[(\frac{2m^8}{m^2n^4})^4=\frac{2^4m^{8*4}}{m^{2*4}n^{4*4}}\]\[=\frac{16m^{32}}{m^{8}n^{16}}\]\[=\frac{16m^{32-8}}{n^{16}}\]\[=\frac{16m^{24}}{n^{16}}\] or \[=16m^{24}n^{-16}\] for no fractions
anonymous
  • anonymous
ah the answers are pure fractions D:
anonymous
  • anonymous
What are the answers given?
anonymous
  • anonymous
8m^24 over n^16 or 16m^24 over n^16 or 8m^12 over n8 and 16 over m^10n^16
anonymous
  • anonymous
So the answer we got was \[\frac{16m^{24}}{n^{16}}\]
anonymous
  • anonymous
I'm lost then/:
anonymous
  • anonymous
Okay let's tackle this one a different way. \[(\frac{2m^8}{m^2n^4})^4\] Let simplify the expression first because we expand the bracket.
anonymous
  • anonymous
\[(\frac{2m^{8-2}}{n^4})^4=(\frac{2m^{6}}{n^4})^4\] Because \[\frac{m^a}{m^b}=m^{a-b}\] Make sense?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
I just need to memorize all this for my quiz tomorrow, it's a closed book test /:
anonymous
  • anonymous
After this \[(\frac{2m^{6}}{n^4})^4=\frac{2^4m^{6*4}}{n^{4*4}}\]\[=\frac{16m^{24}}{n^{16}}\] Because \[(s)^t=s^t\] where s is a constant and \[(m^a)^b=m^{a*b}=m^{ab}\]
anonymous
  • anonymous
yes yes...
anonymous
  • anonymous
So that's the answer :D
anonymous
  • anonymous
thank you<3

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