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anonymous

  • 5 years ago

SIMPLIFY ~ (x^5)^-8x^4

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  1. anonymous
    • 5 years ago
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    \[(x^5)^{-8x^4}=x^{-40x^4}\]

  2. anonymous
    • 5 years ago
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    \[(a^m)^n=a^{mn}\] ^---Rule

  3. anonymous
    • 5 years ago
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    my opinions are fractions.

  4. anonymous
    • 5 years ago
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    \[\frac{1}{x^{40x^4}}\] Is this one of your options?

  5. anonymous
    • 5 years ago
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    no i have 1 over x^160 or 1 over x^36 or x^-36 or i over x^12

  6. anonymous
    • 5 years ago
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    was the question supposed to be \[(x^5)^{-8\times 4}\]?

  7. anonymous
    • 5 years ago
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    If so then the answer is \[\frac{1}{x^{160}}\]

  8. anonymous
    • 5 years ago
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    |dw:1327037411441:dw|

  9. anonymous
    • 5 years ago
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    HELP~

  10. anonymous
    • 5 years ago
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    \[(\frac{2m^8}{m^2n^4})^4=\frac{2^4m^{8*4}}{m^{2*4}n^{4*4}}\]\[=\frac{16m^{32}}{m^{8}n^{16}}\]\[=\frac{16m^{32-8}}{n^{16}}\]\[=\frac{16m^{24}}{n^{16}}\] or \[=16m^{24}n^{-16}\] for no fractions

  11. anonymous
    • 5 years ago
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    ah the answers are pure fractions D:

  12. anonymous
    • 5 years ago
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    What are the answers given?

  13. anonymous
    • 5 years ago
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    8m^24 over n^16 or 16m^24 over n^16 or 8m^12 over n8 and 16 over m^10n^16

  14. anonymous
    • 5 years ago
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    So the answer we got was \[\frac{16m^{24}}{n^{16}}\]

  15. anonymous
    • 5 years ago
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    I'm lost then/:

  16. anonymous
    • 5 years ago
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    Okay let's tackle this one a different way. \[(\frac{2m^8}{m^2n^4})^4\] Let simplify the expression first because we expand the bracket.

  17. anonymous
    • 5 years ago
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    \[(\frac{2m^{8-2}}{n^4})^4=(\frac{2m^{6}}{n^4})^4\] Because \[\frac{m^a}{m^b}=m^{a-b}\] Make sense?

  18. anonymous
    • 5 years ago
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    yeah

  19. anonymous
    • 5 years ago
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    I just need to memorize all this for my quiz tomorrow, it's a closed book test /:

  20. anonymous
    • 5 years ago
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    After this \[(\frac{2m^{6}}{n^4})^4=\frac{2^4m^{6*4}}{n^{4*4}}\]\[=\frac{16m^{24}}{n^{16}}\] Because \[(s)^t=s^t\] where s is a constant and \[(m^a)^b=m^{a*b}=m^{ab}\]

  21. anonymous
    • 5 years ago
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    yes yes...

  22. anonymous
    • 5 years ago
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    So that's the answer :D

  23. anonymous
    • 5 years ago
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    thank you<3

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