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anonymous

  • 5 years ago

An airplane travels 900 miles from Houston to Miami in 6 hours against the wind. On its return trip, with the wind, it only takes 5 hours. Find the rate of the airplane with no wind. Find the rate of the wind.

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  1. anonymous
    • 5 years ago
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    Let the ground speed be x And the wind speed be y AGAINST WIND Distance = 900 miles. Distance = Rate * time 900= (x-y)*6 WITH WIND Distance = 900 miles. Distance = Rate * time 900= (x+y)*5 6x-6y=900 x-y= 150 5x+5y=900 x+y=180 x-y= 150 x+y=180 2x=330 x= 165 mph = ground speed ( With no wind ) y= 15 The ground speed of the plane is 165 mph and wind speed = 15 mph

  2. anonymous
    • 5 years ago
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    Thanks

  3. anonymous
    • 5 years ago
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    No problem :D

  4. anonymous
    • 5 years ago
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    How Did You get x-y= 150 ?

  5. anonymous
    • 5 years ago
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    that's just how you find speed without wind resistance. 900 = (x-y) *6 900/6 = x-y 150 = x-y

  6. anonymous
    • 5 years ago
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    How Did You Get 2x=330 ?

  7. anonymous
    • 5 years ago
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    Never mind Thanks

  8. anonymous
    • 5 years ago
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    so what was the answer?

  9. anonymous
    • 5 years ago
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    x=165 mph y=15 Wind Speed

  10. anonymous
    • 5 years ago
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    I'm sorry I didn't answer I'm doing my homework

  11. anonymous
    • 5 years ago
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    Its Okay I Believe I Know How To Do This Now :D

  12. anonymous
    • 5 years ago
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    Glad I helped :D

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