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Determine the length of MN to the nearest tenth of a centimeter.
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Stacey Warren - Expert brainly.com
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okay give me a little bit of time
for sure. thank you
are you guys figuring it out
sorry i havent done geometry for a while but i got the first step done lol
ok as long as you get it done its all good lol
okay i think i got it but it could be wrong considering i havent done this in a while
1st you would solve for cosine since you know the hyp and are looking for the adjacent
\[\cos 33= x/8.2\]
but you have to get rid of the 8.2 so you use inverse \[(8.2/1)\cos 33=x/8.2 (8.2/1)\]
cancels the 8.2 on the side with te x and leaves you with the x and you get \[(8.2)\cos33\approx6.87=x\]
|dw:1327040409127:dw| so then solve for the missing angle which ends up being 57
and this next part im a little worried its not right but it seems to work so im sorry if its wron but it seems that the nxt triangle is a special triangle or in this case a 30,60,90 triangle |dw:1327040605403:dw|
|dw:1327040766360:dw| and you know the H is now 6.87 so you just plug that in to the eq to get your anwer for MN, ooh and you know its a special triangle cuz along with the other trialgle it = a quadrilateral which as a total of 360 degrees
so i did my best geometry wasnt my strong point but i tried :/