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anonymous

  • 5 years ago

Please show your work and steps when you answer the following question: Determine the length of MN to the nearest tenth of a centimeter. Picture attached below :)

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  1. anonymous
    • 5 years ago
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  2. anonymous
    • 5 years ago
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    okay you need to know sin tan cos rules do you know them?

  3. anonymous
    • 5 years ago
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    yes can u show me step by step how to solve this specific problem. please thanks

  4. anonymous
    • 5 years ago
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    okay give me a little bit of time

  5. anonymous
    • 5 years ago
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    for sure. thank you

  6. anonymous
    • 5 years ago
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    are you guys figuring it out

  7. anonymous
    • 5 years ago
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    sorry i havent done geometry for a while but i got the first step done lol :/

  8. anonymous
    • 5 years ago
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    ok as long as you get it done its all good lol

  9. anonymous
    • 5 years ago
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    okay i think i got it but it could be wrong considering i havent done this in a while

  10. anonymous
    • 5 years ago
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    1st you would solve for cosine since you know the hyp and are looking for the adjacent \[\cos 33= x/8.2\] but you have to get rid of the 8.2 so you use inverse \[(8.2/1)\cos 33=x/8.2 (8.2/1)\] cancels the 8.2 on the side with te x and leaves you with the x and you get \[(8.2)\cos33\approx6.87=x\]

  11. anonymous
    • 5 years ago
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    |dw:1327040409127:dw| so then solve for the missing angle which ends up being 57

  12. anonymous
    • 5 years ago
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    and this next part im a little worried its not right but it seems to work so im sorry if its wron but it seems that the nxt triangle is a special triangle or in this case a 30,60,90 triangle |dw:1327040605403:dw|

  13. anonymous
    • 5 years ago
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    |dw:1327040766360:dw| and you know the H is now 6.87 so you just plug that in to the eq to get your anwer for MN, ooh and you know its a special triangle cuz along with the other trialgle it = a quadrilateral which as a total of 360 degrees

  14. anonymous
    • 5 years ago
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    so i did my best geometry wasnt my strong point but i tried :/

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