anonymous
  • anonymous
Please show your work and steps when you answer the following question: Determine the length of MN to the nearest tenth of a centimeter. Picture attached below :)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
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anonymous
  • anonymous
okay you need to know sin tan cos rules do you know them?
anonymous
  • anonymous
yes can u show me step by step how to solve this specific problem. please thanks

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anonymous
  • anonymous
okay give me a little bit of time
anonymous
  • anonymous
for sure. thank you
anonymous
  • anonymous
are you guys figuring it out
anonymous
  • anonymous
sorry i havent done geometry for a while but i got the first step done lol :/
anonymous
  • anonymous
ok as long as you get it done its all good lol
anonymous
  • anonymous
okay i think i got it but it could be wrong considering i havent done this in a while
anonymous
  • anonymous
1st you would solve for cosine since you know the hyp and are looking for the adjacent \[\cos 33= x/8.2\] but you have to get rid of the 8.2 so you use inverse \[(8.2/1)\cos 33=x/8.2 (8.2/1)\] cancels the 8.2 on the side with te x and leaves you with the x and you get \[(8.2)\cos33\approx6.87=x\]
anonymous
  • anonymous
|dw:1327040409127:dw| so then solve for the missing angle which ends up being 57
anonymous
  • anonymous
and this next part im a little worried its not right but it seems to work so im sorry if its wron but it seems that the nxt triangle is a special triangle or in this case a 30,60,90 triangle |dw:1327040605403:dw|
anonymous
  • anonymous
|dw:1327040766360:dw| and you know the H is now 6.87 so you just plug that in to the eq to get your anwer for MN, ooh and you know its a special triangle cuz along with the other trialgle it = a quadrilateral which as a total of 360 degrees
anonymous
  • anonymous
so i did my best geometry wasnt my strong point but i tried :/

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