## anonymous 4 years ago Please show your work and steps when you answer the following question: Determine the length of MN to the nearest tenth of a centimeter. Picture attached below :)

1. anonymous

2. anonymous

okay you need to know sin tan cos rules do you know them?

3. anonymous

yes can u show me step by step how to solve this specific problem. please thanks

4. anonymous

okay give me a little bit of time

5. anonymous

for sure. thank you

6. anonymous

are you guys figuring it out

7. anonymous

sorry i havent done geometry for a while but i got the first step done lol :/

8. anonymous

ok as long as you get it done its all good lol

9. anonymous

okay i think i got it but it could be wrong considering i havent done this in a while

10. anonymous

1st you would solve for cosine since you know the hyp and are looking for the adjacent $\cos 33= x/8.2$ but you have to get rid of the 8.2 so you use inverse $(8.2/1)\cos 33=x/8.2 (8.2/1)$ cancels the 8.2 on the side with te x and leaves you with the x and you get $(8.2)\cos33\approx6.87=x$

11. anonymous

|dw:1327040409127:dw| so then solve for the missing angle which ends up being 57

12. anonymous

and this next part im a little worried its not right but it seems to work so im sorry if its wron but it seems that the nxt triangle is a special triangle or in this case a 30,60,90 triangle |dw:1327040605403:dw|

13. anonymous

|dw:1327040766360:dw| and you know the H is now 6.87 so you just plug that in to the eq to get your anwer for MN, ooh and you know its a special triangle cuz along with the other trialgle it = a quadrilateral which as a total of 360 degrees

14. anonymous

so i did my best geometry wasnt my strong point but i tried :/