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anonymous

  • 4 years ago

Converting polar to cartesian

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  1. anonymous
    • 4 years ago
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    \[r^2+2r^2\cos \theta \sin \theta\] Steps please.

  2. anonymous
    • 4 years ago
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    \[r = \sqrt{x^2+y^2} \] \[ \cos(\theta) = \frac{x}{r} \] \[ \sin(\theta) = \frac{y}{r} \]

  3. anonymous
    • 4 years ago
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    Trying to replace values now.

  4. anonymous
    • 4 years ago
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    Still can't get it. It's actually what I tried to do many times. Except That instead of of going r = square root, etc. I plugged it in directly. I can't get seperate the 2xy at the end. I can t isolate the y since the answer is x+y = plus or minus 1.

  5. anonymous
    • 4 years ago
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    \[x^2 + y^2 + 2xy = (x+y)^2\]

  6. anonymous
    • 4 years ago
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    ! Crap, I got stuck in a dumb place big time. Thanks.

  7. anonymous
    • 4 years ago
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    Happens sometimes, no worries.

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spraguer (Moderator)
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