anonymous
  • anonymous
An astronaut floating in space throws a small hand tool away from his space shuttle. Which of the following statements is true (A) The velocity of the astronaut is equal and opposite to the velocity of the tool. (B) The kinetic energy of the tool is equal to the kinetic energy of the astronaut. (C) The momentum of the astronaut is greater than the momentum of the tool. (D) The impulse applied to the astronaut is equal and opposite to the impulse applied to the tool. (E) The force applied to the tool is greater than the force applied to the astronaut
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
its D because according to Newton's third law of motion, reaction force equals the action force so in this case the force on the astronaut and the hand tool is the same and acts for the same interval of time.
anonymous
  • anonymous
everything except d option is wrong a) velocity of bag and man need not be equal as only action-reaction forces are equal b)total energy of system remains conserved meaning initial k.e+p.e=final k.e+p.e c)momentum of the system is conserved and the astronaut might have even statred with 0 velocity... d)by action reaction forces, force on tool is equal and opposite to the force on man this leaves us with only d) as force over same time is same as impulse=F*t

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