A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
How do you come to the conclusion that when considering a equilateral triangle inside a circumscribed circle, the height of the triangle is 2/3 of the radius of the circle?
anonymous
 5 years ago
How do you come to the conclusion that when considering a equilateral triangle inside a circumscribed circle, the height of the triangle is 2/3 of the radius of the circle?

This Question is Closed

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.1dw:1327064516603:dw the height is actually greater than the radius sin(30) = h/r = 1/2 > h = r/2 therefore the height of triangle is 3/2 the radius

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1327064957563:dw I've tried to replicate your diagram, with names to the vertexes.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So you're considering triangle CEP or ACP?

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.1CEP, sorry i can't draw :)

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.1dw:1327065261653:dw thats where the "h" comes in

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0naah, you draw just fine. but isnt the height of the triangle AP, not EP?

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.1correct i added the length AE which is just the radius r + r/2 = 3/2r

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OHHH! oops. my bad. Thanks a bunch!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.