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anonymous

  • 5 years ago

A 1kg ball is thrown upwards with a launch speed of 10m/s. Assume air resistance is a constant force of 2.5N. How much nonmechanical energy is generated from launch to the maximum height reached by the ball

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  1. anonymous
    • 5 years ago
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    |dw:1327065330013:dw|here you first find out the height reached by ball acceleration due to gravity is 10 in the downward direction an addition of 2.5m/s^2 acts in the downward direction so add them both as they say air resitance is a contant force apply equation v^2-u^2=2as to find max ht energy=work done (capability) work done=F.s find it!

  2. anonymous
    • 5 years ago
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    as they say non-mechanical energy we say work done by air resistance as mechanical energy=k.e+p.e

  3. anonymous
    • 5 years ago
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    is the max height 4? because for the final answer i got 50, but thats wrong...

  4. anonymous
    • 5 years ago
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    OHHHH

  5. anonymous
    • 5 years ago
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    UGH, nevermind, i messed up my calculations in the calculator, im really tired. THANK YOU SO MUCH.

  6. anonymous
    • 5 years ago
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    .04m

  7. anonymous
    • 5 years ago
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    one more thing, so air is non mechanical energy? and huh? i did w=fdcos =2.5 x 4 = 10 ?

  8. anonymous
    • 5 years ago
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    ya dont worry abt cos@ as angle here is 180 ie w=2.5*0.04*-1

  9. anonymous
    • 5 years ago
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    why did you change it to .04? because i used 4 and that got me the right answer?

  10. anonymous
    • 5 years ago
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    ya ya in metres that is right

  11. anonymous
    • 5 years ago
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    ohhh okay, thanks soo much! seriously!

  12. anonymous
    • 5 years ago
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    omg... if youre still there, what is non mechanical energy and how did you know air resistance was it?

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