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anonymous
 4 years ago
Steps for integrating
anonymous
 4 years ago
Steps for integrating

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{\pi/4}^{\pi/2} (2\sin \theta)^2 d \theta\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i take it this is the same as \[4\int \sin^2(x)dx\] right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0integration by parts twice

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0gimmick is to write \[\sin^2(x)=1\cos^2(x)=\frac{1}{2}\frac{1}{2}\cos(2x)\] one of those "double angle formula's backwards"

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0best trick is actually to look in the back of the textbook for the "reduction formulas" but if you recall all those annoying trig identities, this is the "lowering powers" formula

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ah, thanks. I get it.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0sin reduction:\[\int sin^ndx=\frac{1}{n}sin^{n1}cos+\frac{n1}{n}\int sin^{n2}dx\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah that one that i can't remember. the entire content of most calc 2 courses is contained on the back two pages of the text

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I've never seen that formula but wouldn't that give me another answer?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0the answer might "look" different, but since trig has identities that are equal it will have the same value in the end

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0using integration by parts ends up with that formula for reduction
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