anonymous
  • anonymous
Steps for integrating
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[\int\limits_{\pi/4}^{\pi/2} (2\sin \theta)^2 d \theta\]
anonymous
  • anonymous
i take it this is the same as \[4\int \sin^2(x)dx\] right?
anonymous
  • anonymous
Yes

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

dumbcow
  • dumbcow
integration by parts twice
anonymous
  • anonymous
gimmick is to write \[\sin^2(x)=1-\cos^2(x)=\frac{1}{2}-\frac{1}{2}\cos(2x)\] one of those "double angle formula's backwards"
anonymous
  • anonymous
best trick is actually to look in the back of the textbook for the "reduction formulas" but if you recall all those annoying trig identities, this is the "lowering powers" formula
anonymous
  • anonymous
Ah, thanks. I get it.
anonymous
  • anonymous
yw
amistre64
  • amistre64
sin reduction:\[\int sin^ndx=-\frac{1}{n}sin^{n-1}cos+\frac{n-1}{n}\int sin^{n-2}dx\]
anonymous
  • anonymous
yeah that one that i can't remember. the entire content of most calc 2 courses is contained on the back two pages of the text
anonymous
  • anonymous
I've never seen that formula but wouldn't that give me another answer?
amistre64
  • amistre64
the answer might "look" different, but since trig has identities that are equal it will have the same value in the end
amistre64
  • amistre64
using integration by parts ends up with that formula for reduction

Looking for something else?

Not the answer you are looking for? Search for more explanations.