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I did that in class todya but i didnt get the right answer..
what did you get for the first one?
(2x+4)+(2x+4) 4x+2x+4+4+2x+4+4 8x+16
it looks like you are multiplying and adding instead of adding. the parentheses here are unnecessary
when it says to add, I would add. and when it says to multiply, id multiply. but thats just me set in my ways :)
let's imagine for a moment that x was ten (x is a variable, but it could be ten) then \[2x+4=2\times 10+4=24\] and \[24+24=48\]
I thought it was like this |dw:1327066387934:dw|
multiplication distributes over addition. so if you had \[(2x+4)(2x+4)\] you would use the distributive law, just like if you had \[24\times 24\]
But wheres the x?
addition is commutative you can remove brackets when you have ONLY addition
but addition is the same as "combine like terms" just as you would with arithmetic 24 + 24 ______ 48 2x + 4 + 2x + 4 __________ 4x + 8
2x+4 (+) 2x+4 -------- 4x+ 8 2x+4 (x) 2x+4 --------- 8x+16 4xx+8x ----------------- 4x^2+16x+16
Why would it be 4x^2+16x+16?
@inopeki i was making an analogy. the work you do with variables is a generalization of the work you do in arithmetic, and if it doesn't work with arithmetic it certainly doesn't work with variables, because the variable could be a number, that is you could replace the variable by a number
becasue thats what happens when you multiply stuff
so basically just add them up?
2x+4 (+) 2x+4 -------- 4x+ 8
imagine your job was to add \[24+24\]\ what would you do? line them up and add
5+3 = 8 (x) 2+4 = 6 ------------ 20+12 10+6 -------------- 10+26+12 = 48
24 +24 ---- 48
and similarly 2x + 4 + 2x + 4 __________ 4x + 8
Oh! Give me another example?
(3x+5) +(4x+1) -------- 7x+6
Yes! :D Thanks