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anonymous
 5 years ago
Radius of incircle of a triangle = Area of triangle/Semiperimeter of the triangle. How?
anonymous
 5 years ago
Radius of incircle of a triangle = Area of triangle/Semiperimeter of the triangle. How?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no....my textbook just says that formula. we're supposed to apply that formula in approrpriate sums. im asking for the formula's proof :P

phi
 5 years ago
Best ResponseYou've already chosen the best response.0The center of the incircle is the intersection of the angle bisectors You end up with 6 right triangles for example, 2 with sides a and r add up the area of each

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0kind of.....not fully

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh. wait. stop right there. :P I got it :D Thanks a lot :)

phi
 5 years ago
Best ResponseYou've already chosen the best response.0These 2 triangles are congruent. Angle bisector makes angles =, 90 deg =, 3rd angle must be equal, plus they have equal side (radius)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I understood, phi. I intitally had problems with how you derived it, and then now i got it. Thanks.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Got it as in I got the answer. :)

phi
 5 years ago
Best ResponseYou've already chosen the best response.0It's nice when the light bulb goes on!
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