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anonymous

  • 5 years ago

Radius of incircle of a triangle = Area of triangle/Semiperimeter of the triangle. How?

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  1. LollyLau
    • 5 years ago
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    Who said that?

  2. phi
    • 5 years ago
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    |dw:1327066868311:dw|

  3. LollyLau
    • 5 years ago
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    You meant the sum?

  4. anonymous
    • 5 years ago
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    no....my textbook just says that formula. we're supposed to apply that formula in approrpriate sums. im asking for the formula's proof :P

  5. anonymous
    • 5 years ago
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    says* = states

  6. phi
    • 5 years ago
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    The center of the incircle is the intersection of the angle bisectors You end up with 6 right triangles for example, 2 with sides a and r add up the area of each

  7. LollyLau
    • 5 years ago
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    ???

  8. phi
    • 5 years ago
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    Not clear yet?

  9. anonymous
    • 5 years ago
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    kind of.....not fully

  10. phi
    • 5 years ago
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    |dw:1327067491979:dw|

  11. anonymous
    • 5 years ago
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    oh. wait. stop right there. :P I got it :D Thanks a lot :)

  12. phi
    • 5 years ago
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    |dw:1327067560181:dw|

  13. phi
    • 5 years ago
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    These 2 triangles are congruent. Angle bisector makes angles =, 90 deg =, 3rd angle must be equal, plus they have equal side (radius)

  14. anonymous
    • 5 years ago
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    I understood, phi. I intitally had problems with how you derived it, and then now i got it. Thanks.

  15. anonymous
    • 5 years ago
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    Got it as in I got the answer. :)

  16. phi
    • 5 years ago
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    It's nice when the light bulb goes on!

  17. anonymous
    • 5 years ago
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    lol yup, totally :D!

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