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anonymous

  • 5 years ago

How many possible three-digit passwords can be formed using digits 0 through 9 if digits are repeated? 30 , 720 , 1,000

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  1. amistre64
    • 5 years ago
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    10 options for the 1st number 10 options each for those 10; 10*10 and 10 options each for those: 10*10*10

  2. anonymous
    • 5 years ago
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    which is the same as asking "how many three digit numbers are there?"

  3. LollyLau
    • 5 years ago
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    what do you mean by "digits are repeated"?

  4. amistre64
    • 5 years ago
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    000 to 999

  5. LollyLau
    • 5 years ago
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    does that mean that at least two of them must be the same?

  6. anonymous
    • 5 years ago
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    idk its on my math test

  7. LollyLau
    • 5 years ago
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    -.-

  8. LollyLau
    • 5 years ago
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    go ask your teacher

  9. amistre64
    • 5 years ago
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    lol, i hate interpreting word problems

  10. amistre64
    • 5 years ago
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    do digits have to be repeated? or CAN they be repeated?

  11. anonymous
    • 5 years ago
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    no , she doesnt even know

  12. LollyLau
    • 5 years ago
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    how can she don't know???????

  13. amistre64
    • 5 years ago
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    most likely I would say it means that the option is left open that they CAN be repeated, but is not a requirement

  14. anonymous
    • 5 years ago
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    bc shes dumb like that , its an online class & shes not even a math teacher

  15. LollyLau
    • 5 years ago
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    but its given =.=

  16. amistre64
    • 5 years ago
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    lets not degrade the teachers please.

  17. anonymous
    • 5 years ago
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    lol

  18. anonymous
    • 5 years ago
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    Here is a good way to think of such things, I find...Let some arbitrary password be \[x_1x_2x_3\] (where we mean digits next to each other, not multiplication). So we have \[x_1,x_2,x_3 \in \{0,1,2,...,9\}\]Now, each position has the choice of 10 digits, 0 through 9 inclusive. So the answer is 10x10x10 = 10^3 = 1000.

  19. anonymous
    • 5 years ago
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    If the password was n digits long, then the number of possible choices is \[10^n\]

  20. anonymous
    • 5 years ago
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    amistre64 has a good way of thinking about it, since your first digit has 10 options, and for each of those first digits there are 10 options for your second digit. So there are 10*10=100 options for two digits. Now for each of those 100 options, there are 10 options for your third digit. So for any three digits, there are 100*10 options.

  21. anonymous
    • 5 years ago
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    logically speaking... 3 digit password starts from 000 to 999.... now u can count how many of them are between 000 & 999 inclusive. It will include all possible repeating numbers.

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