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anonymous
 5 years ago
How many possible threedigit passwords can be formed using digits 0 through 9 if digits are repeated?
30 ,
720 ,
1,000
anonymous
 5 years ago
How many possible threedigit passwords can be formed using digits 0 through 9 if digits are repeated? 30 , 720 , 1,000

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.310 options for the 1st number 10 options each for those 10; 10*10 and 10 options each for those: 10*10*10

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0which is the same as asking "how many three digit numbers are there?"

LollyLau
 5 years ago
Best ResponseYou've already chosen the best response.0what do you mean by "digits are repeated"?

LollyLau
 5 years ago
Best ResponseYou've already chosen the best response.0does that mean that at least two of them must be the same?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0idk its on my math test

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3lol, i hate interpreting word problems

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3do digits have to be repeated? or CAN they be repeated?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no , she doesnt even know

LollyLau
 5 years ago
Best ResponseYou've already chosen the best response.0how can she don't know???????

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3most likely I would say it means that the option is left open that they CAN be repeated, but is not a requirement

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0bc shes dumb like that , its an online class & shes not even a math teacher

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3lets not degrade the teachers please.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Here is a good way to think of such things, I find...Let some arbitrary password be \[x_1x_2x_3\] (where we mean digits next to each other, not multiplication). So we have \[x_1,x_2,x_3 \in \{0,1,2,...,9\}\]Now, each position has the choice of 10 digits, 0 through 9 inclusive. So the answer is 10x10x10 = 10^3 = 1000.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If the password was n digits long, then the number of possible choices is \[10^n\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0amistre64 has a good way of thinking about it, since your first digit has 10 options, and for each of those first digits there are 10 options for your second digit. So there are 10*10=100 options for two digits. Now for each of those 100 options, there are 10 options for your third digit. So for any three digits, there are 100*10 options.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0logically speaking... 3 digit password starts from 000 to 999.... now u can count how many of them are between 000 & 999 inclusive. It will include all possible repeating numbers.
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