A community for students.
Here's the question you clicked on:
← 55 members online
 0 viewing
anonymous
 5 years ago
Why is Fe3O4 Iron(II) diiron(III) oxide?
anonymous
 5 years ago
Why is Fe3O4 Iron(II) diiron(III) oxide?

This Question is Closed

JFraser
 5 years ago
Best ResponseYou've already chosen the best response.1same reason as the earlier question, just slightly more complicated. Oxygen has to be a 2. 4 of them make the total negative charge 8. With 3 irons, there's no way for the charge to be distributed evenly. 8/3 is not a whole #. The easiest way to split up the charge is to have 1 iron be +2, and 2 irons be +3 each 2 + 3 + 3 = 8.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.