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anonymous
 4 years ago
Why is Fe3O4 Iron(II) diiron(III) oxide?
anonymous
 4 years ago
Why is Fe3O4 Iron(II) diiron(III) oxide?

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JFraser
 4 years ago
Best ResponseYou've already chosen the best response.1same reason as the earlier question, just slightly more complicated. Oxygen has to be a 2. 4 of them make the total negative charge 8. With 3 irons, there's no way for the charge to be distributed evenly. 8/3 is not a whole #. The easiest way to split up the charge is to have 1 iron be +2, and 2 irons be +3 each 2 + 3 + 3 = 8.
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