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amistre64

  • 4 years ago

How many different groups of students can show up for a seminar with an enrollment of 17? What? and How is the answer, 131072?

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  1. AravindG
    • 4 years ago
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    easy

  2. amistre64
    • 4 years ago
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    "easy" doent clarify anything ....

  3. AravindG
    • 4 years ago
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    just take diff cases and add

  4. amistre64
    • 4 years ago
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    diff cases of what tho?

  5. AravindG
    • 4 years ago
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    u see its said enrollment shud be 17

  6. AravindG
    • 4 years ago
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    take case 1 :let there be 17 groups

  7. AravindG
    • 4 years ago
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    nxt

  8. AravindG
    • 4 years ago
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    9 groups

  9. AravindG
    • 4 years ago
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    wait a minute

  10. AravindG
    • 4 years ago
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    lemme sort this out

  11. anonymous
    • 4 years ago
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    I have no clue for this one, from where did you get this question?

  12. amistre64
    • 4 years ago
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    got it off a myMathLab site. part of some homework questions for a finite math course.

  13. amistre64
    • 4 years ago
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    I like how Arav says "easy" then has to "sort it out". ...

  14. anonymous
    • 4 years ago
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    I got it! (with a little bit of help from a friend), actually the problem is easy the main thing is to understand "with an enrollment of 17"; I interpreted as there are 17 people enrolled. Any subset of the \(17\) could show up in the seminar, and we know there are \(2^{17}=131072\) subsets of a \(17\) element set.

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