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anonymous
 4 years ago
Given the system of equations, what is the solution?
2x + 3y = 2
3x  4y = 20
anonymous
 4 years ago
Given the system of equations, what is the solution? 2x + 3y = 2 3x  4y = 20

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0solve either by substitution or by multiplying the first by 3/2 and subtracting that from the second to find y and then solve for x, or use a matrix method...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I will solve by elimination: multiply the first equation by 3/2 to get: \[3x + \frac{9}{2}y = 3\] comparing this with the second equation which is \[3x  4y = 20\] we see that the coefficient of x (the number multiplying it) in both these equations is 3. So if we subtract one equation from the other (either will do) we will eliminate x and be left with an equation in y only which we can solve for y: \[3x4y (3x + \frac{9}{2}y) = 203\] \[4y  \frac{9}{2}y = 17\] \[\frac{17}{2}y = 17\] \[y=2\] Now substitute y=2 into ANY one of your starting equations (it doesn't matter which one) to find x: \[3x  4(2) = 20\] \[3x = 20  8\] \[3x=12\] \[x=4\] So x=4, y=2
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