anonymous
  • anonymous
Am I correct? Find all the real fourth roots of the fraction.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
..
anonymous
  • anonymous
\[256 \over 2401\]
anonymous
  • anonymous
My answers were:

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anonymous
  • anonymous
4 over 7, and 16 over 49
anonymous
  • anonymous
As in What are all the real fourth roots of -16?
anonymous
  • anonymous
Well it didn't say fraction, I just added that.
anonymous
  • anonymous
I'm wondering if I should solve the fraction first, or get the square roots of both numbers.
anonymous
  • anonymous
Yes, solve the fraction first .
anonymous
  • anonymous
0.106
anonymous
  • anonymous
YOUR RIGHT! 256 / 2 401 = 0.106622241 how did i get it? simple just go to google and put your fraction like this "/" and but a equal at the end like this . http://www.google.com/#sclient=psy-ab&fhp=1&hl=en&fhp=1&source=hp&q=256%2F2401+%3D&pbx=1&oq=256%2F2401+%3D&aq=f&aqi=&aql=&gs_sm=e&gs_upl=4118l10707l1l10952l7l6l0l0l0l0l294l13
anonymous
  • anonymous
So it cannot be anything -?
anonymous
  • anonymous
no the answer you pick is right! the others are not.
anonymous
  • anonymous
Thank you!
anonymous
  • anonymous
Your welcome :) i'm here to help anytime
anonymous
  • anonymous
Thanks

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