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anonymous

  • 5 years ago

Can someone please help me with a matrice question?

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  1. anonymous
    • 5 years ago
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  2. anonymous
    • 5 years ago
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    I got the answer as to what the vertices of th etriangle wld be but like does the transformation represent?

  3. anonymous
    • 5 years ago
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    Please don't use doc. just copy and paste question and chooses

  4. anonymous
    • 5 years ago
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    lol whtvr I used a pdf and most ppl dont have an issue with that

  5. anonymous
    • 5 years ago
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    It is coming from a pdf format so I have to print screen it

  6. anonymous
    • 5 years ago
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    Can u help me?

  7. anonymous
    • 5 years ago
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    huh

  8. anonymous
    • 5 years ago
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    ok i will try :/

  9. anonymous
    • 5 years ago
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    LOL ppl can help

  10. anonymous
    • 5 years ago
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    k

  11. anonymous
    • 5 years ago
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    im "traying to try"

  12. anonymous
    • 5 years ago
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    lol

  13. phi
    • 5 years ago
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    Do you know how to do the matrix multiplication?

  14. anonymous
    • 5 years ago
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    rows by columns?

  15. anonymous
    • 5 years ago
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    yes

  16. anonymous
    • 5 years ago
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    I did that

  17. anonymous
    • 5 years ago
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    I got the answer of the points of the triangle but i need to know abt the transformation

  18. anonymous
    • 5 years ago
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    you need to represent the transformation as a triangle?

  19. anonymous
    • 5 years ago
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    how it see pictorially?

  20. anonymous
    • 5 years ago
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    ummm ok they gave you the points of the traingle and then it asks u to transform by multiplying it by matrix A

  21. anonymous
    • 5 years ago
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    I was able to get the points of the two transformed triangles but i dont get what the transformation is

  22. anonymous
    • 5 years ago
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    tl;dr \[\Large \begin{array}{l} A = \left[ {\begin{array}{*{20}{c}} 0&{ - 1}\\ 1&0 \end{array}} \right]\\ T = \left[ {\begin{array}{*{20}{c}} {\begin{array}{*{20}{c}} 1&2&3 \end{array}}\\ {\begin{array}{*{20}{c}} 1&4&2 \end{array}} \end{array}} \right]\\ AT = \left[ {\begin{array}{*{20}{c}} {\begin{array}{*{20}{c}} { - 1}&{ - 4}&{ - 2} \end{array}}\\ {\begin{array}{*{20}{c}} 1&2&3 \end{array}} \end{array}} \right]\\ AAT = \left[ {\begin{array}{*{20}{c}} {\begin{array}{*{20}{c}} { - 1}&{ - 2}&{ - 3} \end{array}}\\ {\begin{array}{*{20}{c}} { - 1}&{ - 4}&{ - 2} \end{array}} \end{array}} \right] \end{array}\]

  23. anonymous
    • 5 years ago
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    Thanks FSM:D

  24. anonymous
    • 5 years ago
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    but like how wld i explain the transformation?

  25. anonymous
    • 5 years ago
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  26. anonymous
    • 5 years ago
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    i dont know, may be you could construct some ideas from that.. sorry

  27. anonymous
    • 5 years ago
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    i think in the a) AT; the triange rotates

  28. anonymous
    • 5 years ago
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    Thnaks :D

  29. anonymous
    • 5 years ago
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    I drew all the triangles on a graph

  30. anonymous
    • 5 years ago
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    and in AAT; it rotates again?

  31. anonymous
    • 5 years ago
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    So it easier to see what happennned

  32. anonymous
    • 5 years ago
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    AAT it gets flipped in the y an dthen x axis

  33. anonymous
    • 5 years ago
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    It gets mirrored in the y=-x axis

  34. anonymous
    • 5 years ago
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    but AT is confusing

  35. anonymous
    • 5 years ago
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    It get mirrored in the y axis

  36. anonymous
    • 5 years ago
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    but then there seems to be another transformation

  37. anonymous
    • 5 years ago
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    i think it also he inverse

  38. anonymous
    • 5 years ago
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    I am not sure and doesnt seem like any1 else is either

  39. anonymous
    • 5 years ago
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  40. anonymous
    • 5 years ago
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    Thanks that was helpful :D

  41. anonymous
    • 5 years ago
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    thanks it was a really good question

  42. phi
    • 5 years ago
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    A is rotating the triangle 90º counter clockwise around the origin. Notice that 2 of the rotations gives you 180º

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is replying to Can someone tell me what button the professor is hitting...

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