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anonymous
 4 years ago
Can someone please help me with a matrice question?
anonymous
 4 years ago
Can someone please help me with a matrice question?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I got the answer as to what the vertices of th etriangle wld be but like does the transformation represent?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Please don't use doc. just copy and paste question and chooses

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol whtvr I used a pdf and most ppl dont have an issue with that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It is coming from a pdf format so I have to print screen it

phi
 4 years ago
Best ResponseYou've already chosen the best response.2Do you know how to do the matrix multiplication?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I got the answer of the points of the triangle but i need to know abt the transformation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you need to represent the transformation as a triangle?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how it see pictorially?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ummm ok they gave you the points of the traingle and then it asks u to transform by multiplying it by matrix A

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I was able to get the points of the two transformed triangles but i dont get what the transformation is

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0tl;dr \[\Large \begin{array}{l} A = \left[ {\begin{array}{*{20}{c}} 0&{  1}\\ 1&0 \end{array}} \right]\\ T = \left[ {\begin{array}{*{20}{c}} {\begin{array}{*{20}{c}} 1&2&3 \end{array}}\\ {\begin{array}{*{20}{c}} 1&4&2 \end{array}} \end{array}} \right]\\ AT = \left[ {\begin{array}{*{20}{c}} {\begin{array}{*{20}{c}} {  1}&{  4}&{  2} \end{array}}\\ {\begin{array}{*{20}{c}} 1&2&3 \end{array}} \end{array}} \right]\\ AAT = \left[ {\begin{array}{*{20}{c}} {\begin{array}{*{20}{c}} {  1}&{  2}&{  3} \end{array}}\\ {\begin{array}{*{20}{c}} {  1}&{  4}&{  2} \end{array}} \end{array}} \right] \end{array}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but like how wld i explain the transformation?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i dont know, may be you could construct some ideas from that.. sorry

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think in the a) AT; the triange rotates

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I drew all the triangles on a graph

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and in AAT; it rotates again?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So it easier to see what happennned

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0AAT it gets flipped in the y an dthen x axis

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It gets mirrored in the y=x axis

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It get mirrored in the y axis

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but then there seems to be another transformation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think it also he inverse

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am not sure and doesnt seem like any1 else is either

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks that was helpful :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks it was a really good question

phi
 4 years ago
Best ResponseYou've already chosen the best response.2A is rotating the triangle 90º counter clockwise around the origin. Notice that 2 of the rotations gives you 180º
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