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anonymous
 5 years ago
8. Test the series for convergence or divergence:
summantion (n= infinite to1)[n!/(2.5.8..............(3n+2)
anonymous
 5 years ago
8. Test the series for convergence or divergence: summantion (n= infinite to1)[n!/(2.5.8..............(3n+2)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{n=1}^{\infty}(n!/2.5.8..................(3n+2))\] its like this

Zarkon
 5 years ago
Best ResponseYou've already chosen the best response.2compute \[\lim_{n\rightarrow\infty}\left\frac{a_{n+1}}{a_n}\right\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you show me all steps please :(

Zarkon
 5 years ago
Best ResponseYou've already chosen the best response.2all of them...hmmm...I'm pretty lazy...I'll just get you started

Zarkon
 5 years ago
Best ResponseYou've already chosen the best response.2\[a_n=\frac{n!}{2\cdot5\cdot8\cdots(3n+2)}\]

Zarkon
 5 years ago
Best ResponseYou've already chosen the best response.2\[\frac{a_n+1}{a_n}=\frac{\frac{(n+1)!}{2\cdot5\cdot8\cdots(3(n+1)+2)}}{\frac{n!}{2\cdot5\cdot8\cdots(3n+2)}}\]

Zarkon
 5 years ago
Best ResponseYou've already chosen the best response.2\[=\frac{n+1}{3(n+1)+2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0love you for this :))
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