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anonymous

  • 5 years ago

CD is tangent to the circle and segment AE is perpendicular to segment AC. If a radius of the circle measures 12 in., which is the value of DF + AF?

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  1. anonymous
    • 5 years ago
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    It uses this picture

  2. vishal_kothari
    • 5 years ago
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    wait for a minute...

  3. anonymous
    • 5 years ago
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    It's multiple choice; these are the answers given: A. 28 + 5(sqrt 3) B. 28 - 4(sqrt 3) C. 24 - 4(sqrt 3) D. 21 + 2(sqrt 3)

  4. vishal_kothari
    • 5 years ago
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    C.

  5. anonymous
    • 5 years ago
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    Can you explain how?

  6. vishal_kothari
    • 5 years ago
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    in which grade you are in?

  7. anonymous
    • 5 years ago
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    8th, but I'm taking Geometry.

  8. vishal_kothari
    • 5 years ago
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    the concept i used is taught in 11th grade...

  9. anonymous
    • 5 years ago
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    Try me

  10. vishal_kothari
    • 5 years ago
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    what?

  11. anonymous
    • 5 years ago
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    As in, let's see if I can understand it.

  12. vishal_kothari
    • 5 years ago
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    in AFE, tan60=AE/AF \[\sqrt{3}\]=12/AF AF=4\[\sqrt{3}\]

  13. anonymous
    • 5 years ago
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    whoops, sorry

  14. vishal_kothari
    • 5 years ago
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    why you are sorry...

  15. anonymous
    • 5 years ago
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    because I accidentally typed a phrase that was incongruous in our conversation?

  16. anonymous
    • 5 years ago
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    oh well

  17. vishal_kothari
    • 5 years ago
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    u in which country...

  18. anonymous
    • 5 years ago
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    America?

  19. anonymous
    • 5 years ago
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    This question was posed to me in my geometry class - are u sure there's no easier way to solve it? I was thinking something to do with 30-60-90 triangles

  20. vishal_kothari
    • 5 years ago
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    i also used that...

  21. anonymous
    • 5 years ago
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    ok

  22. anonymous
    • 5 years ago
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    well i understand how AF = 4(sqrt 3)

  23. anonymous
    • 5 years ago
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    what im not getting is how to solve for DF

  24. vishal_kothari
    • 5 years ago
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    really...

  25. vishal_kothari
    • 5 years ago
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    u understand how to get AF..

  26. anonymous
    • 5 years ago
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    well, i didn't understand how u explained it, but i did arrive at the same answer - 4(sqrt 3)

  27. anonymous
    • 5 years ago
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    so let's see - if we use 30-60-90 triangles as our basis, then DF = 2CF, correct?

  28. vishal_kothari
    • 5 years ago
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    if i will give you the value of CF.. THAN COULD U FIND DF...

  29. vishal_kothari
    • 5 years ago
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    CF=AC-AF=12-4\[\sqrt{3}\]

  30. anonymous
    • 5 years ago
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    I think I could, but what I'm getting is not 24, like you say it is. That's why I'm going to show you how I would solve it, and I ask that you please correct me if I am wrong. AC = 12, because it is a radius. We have determined that AF = 4(sqrt 3). 12 - 4(sqrt 3) =

  31. anonymous
    • 5 years ago
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    yeah ok good, we agree so far

  32. anonymous
    • 5 years ago
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    so 12 - 4(sqrt 3) = 5.07179677

  33. anonymous
    • 5 years ago
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    Using 30-60-90 Triangles, DF is 2x this, or 10.1435935

  34. vishal_kothari
    • 5 years ago
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    YA..

  35. vishal_kothari
    • 5 years ago
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    ARE U AT FACEBOOK...

  36. anonymous
    • 5 years ago
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    no

  37. anonymous
    • 5 years ago
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    okay

  38. anonymous
    • 5 years ago
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    good, thank you for your time

  39. vishal_kothari
    • 5 years ago
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    WELCOME

  40. anonymous
    • 5 years ago
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    so i am new to this website - how do i thank you in return?

  41. vishal_kothari
    • 5 years ago
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    IT'S 12:25 A.M. HERE..

  42. anonymous
    • 5 years ago
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    oh sorry

  43. anonymous
    • 5 years ago
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    why are you using a computer at 12:30?

  44. anonymous
    • 5 years ago
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    oh well

  45. anonymous
    • 5 years ago
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    so do i thank you by clicking good answer on all of your responses?

  46. vishal_kothari
    • 5 years ago
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    YOUR WISH..

  47. anonymous
    • 5 years ago
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    i told you im new - im not sure what to do now

  48. vishal_kothari
    • 5 years ago
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    WELL IT WAS MY BROTHER'S BIRTHDAY .....SO 12:30..

  49. vishal_kothari
    • 5 years ago
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    GIVE ME A MEDAL AND YOUR LEVEL WILL INCREASE..

  50. anonymous
    • 5 years ago
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    can i give u multiple if i feel like it?

  51. anonymous
    • 5 years ago
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    oh w8, other people have to

  52. anonymous
    • 5 years ago
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    all right, thank you again for all your help

  53. vishal_kothari
    • 5 years ago
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    WELCOME

  54. vishal_kothari
    • 5 years ago
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    ASK MORE QUESTIONS IF YOU HAVE ...

  55. anonymous
    • 5 years ago
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    I'm fine for now, but I definitely will when I have another one.

  56. vishal_kothari
    • 5 years ago
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    OK

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