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It uses this picture

wait for a minute...

Can you explain how?

in which grade you are in?

8th, but I'm taking Geometry.

the concept i used is taught in 11th grade...

Try me

what?

As in, let's see if I can understand it.

in AFE,
tan60=AE/AF
\[\sqrt{3}\]=12/AF
AF=4\[\sqrt{3}\]

whoops, sorry

why you are sorry...

because I accidentally typed a phrase that was incongruous in our conversation?

oh well

u in which country...

America?

i also used that...

ok

well i understand how AF = 4(sqrt 3)

what im not getting is how to solve for DF

really...

u understand how to get AF..

well, i didn't understand how u explained it, but i did arrive at the same answer - 4(sqrt 3)

so let's see - if we use 30-60-90 triangles as our basis, then DF = 2CF, correct?

if i will give you the value of CF.. THAN COULD U FIND DF...

CF=AC-AF=12-4\[\sqrt{3}\]

yeah ok good, we agree so far

so 12 - 4(sqrt 3) = 5.07179677

Using 30-60-90 Triangles, DF is 2x this, or 10.1435935

YA..

ARE U AT FACEBOOK...

no

okay

good, thank you for your time

WELCOME

so i am new to this website - how do i thank you in return?

IT'S 12:25 A.M. HERE..

oh sorry

why are you using a computer at 12:30?

oh well

so do i thank you by clicking good answer on all of your responses?

YOUR WISH..

i told you im new - im not sure what to do now

WELL IT WAS MY BROTHER'S BIRTHDAY .....SO 12:30..

GIVE ME A MEDAL AND YOUR LEVEL WILL INCREASE..

can i give u multiple if i feel like it?

oh w8, other people have to

all right, thank you again for all your help

WELCOME

ASK MORE QUESTIONS IF YOU HAVE ...

I'm fine for now, but I definitely will when I have another one.