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anonymous
 4 years ago
What is the third–degree polynomial function such that f(0) = –18 and whose zeros are 1, 2, and 3?
anonymous
 4 years ago
What is the third–degree polynomial function such that f(0) = –18 and whose zeros are 1, 2, and 3?

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Hero
 4 years ago
Best ResponseYou've already chosen the best response.1wait, lol. I didn't see the f(0) = 18 part

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh. so what do i do im soooo confused!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you know it is \[f(x)=a(x1)(x2)(x3)\] and you also know the constant is 18 since \[f(0)=18\] the only thing you don't know is "a"

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[a\times 1\times 2\times 3=6a=18\] therefore \[a=3\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and so your answer is \[f(x)=3(x1)(x2)(x3)=3 x^3+18 x^233 x+18\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@luis unfortunately when you tack on 18 at the end of the product, the zeros are no longer 1,2 and 3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol i hate algebra!!!! its mean
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