## anonymous 4 years ago What is the third–degree polynomial function such that f(0) = –18 and whose zeros are 1, 2, and 3?

1. anonymous

Ahh thank you!!!

2. Hero

wait, lol. I didn't see the f(0) = -18 part

3. anonymous

oh. so what do i do im soooo confused!

4. anonymous

you know it is $f(x)=a(x-1)(x-2)(x-3)$ and you also know the constant is 18 since $f(0)=18$ the only thing you don't know is "a"

5. anonymous

$a\times -1\times -2\times -3=-6a=18$ therefore $a=-3$

6. anonymous

and so your answer is $f(x)=-3(x-1)(x-2)(x-3)=-3 x^3+18 x^2-33 x+18$

7. anonymous

@luis unfortunately when you tack on -18 at the end of the product, the zeros are no longer 1,2 and 3

8. Hero

satellite is the master

9. anonymous

of disaster!

10. anonymous

lol i hate algebra!!!! its mean