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anonymous

  • 5 years ago

Solve the problem.

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  1. anonymous
    • 5 years ago
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    \[6\overline{.25}= P/Q\]

  2. 2bornot2b
    • 5 years ago
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    Do you want to express 6.25252525..........as P/Q, where P and Q are coprimes?

  3. anonymous
    • 5 years ago
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    yes i do want to express it like that... and it just shows it like that on my paper p/q as a fraction.

  4. 2bornot2b
    • 5 years ago
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    First I say let x = 6.252525........... Now I multiply both sides by 10^4

  5. 2bornot2b
    • 5 years ago
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    (10^4)x=62525.2525...

  6. anonymous
    • 5 years ago
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    On my homework it says to multiply it by a hundred or that is what my teacher told me.

  7. 2bornot2b
    • 5 years ago
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    You may do that, it doesn't matter

  8. 2bornot2b
    • 5 years ago
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    Say at first you multiply by 100, then multiply by 10 In my problem I am first multiplying by 10000, and then by 1000

  9. anonymous
    • 5 years ago
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    Oh well i am not sure how that is why i posted it on here haha.

  10. 2bornot2b
    • 5 years ago
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    what do you mean by "Oh well i am not sure how that is"

  11. 2bornot2b
    • 5 years ago
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    Any way, since I see you are already familiar with the procedure. I am stating it once again, in a better way, so that you understand the thing better.

  12. anonymous
    • 5 years ago
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    I am not sure how to multiply it by a 100 like i don't know how to solve it.

  13. 2bornot2b
    • 5 years ago
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    STEP 1. Assume x = (the number given to you)

  14. 2bornot2b
    • 5 years ago
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    STEP 2. Multiply both sides by 10^n

  15. 2bornot2b
    • 5 years ago
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    STEP 3: Multiply both sides by 10^m

  16. 2bornot2b
    • 5 years ago
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    So now you have two equations (Not m must be lesser than n)

  17. 2bornot2b
    • 5 years ago
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    Subtract the second equation from the first

  18. 2bornot2b
    • 5 years ago
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    Now you will get a good equation which looks like P/Q

  19. 2bornot2b
    • 5 years ago
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    I am solving the problem given by you....

  20. anonymous
    • 5 years ago
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    yes i know.

  21. 2bornot2b
    • 5 years ago
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    |dw:1327088110491:dw|

  22. anonymous
    • 5 years ago
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    now what do i do after this doesnt it have to be turned into an equation.

  23. 2bornot2b
    • 5 years ago
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    |dw:1327088136907:dw|

  24. 2bornot2b
    • 5 years ago
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    |dw:1327088233575:dw|

  25. 2bornot2b
    • 5 years ago
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    |dw:1327088285898:dw|

  26. 2bornot2b
    • 5 years ago
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    |dw:1327088337495:dw|

  27. 2bornot2b
    • 5 years ago
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    So I have expressed x as P/Q, and x is equal to 6.2525...

  28. 2bornot2b
    • 5 years ago
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    Did you understand?

  29. anonymous
    • 5 years ago
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    So the last part is p/q? And yes for the most part i did.

  30. 2bornot2b
    • 5 years ago
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    Of course, the last part is p/q

  31. 2bornot2b
    • 5 years ago
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    However, you must simplify that, to get the actual p and q

  32. anonymous
    • 5 years ago
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    alright just making sure... so it does not need to be reduced

  33. 2bornot2b
    • 5 years ago
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    Yes, you need to reduce ofcourse

  34. anonymous
    • 5 years ago
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    alright

  35. 2bornot2b
    • 5 years ago
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    You can't leave it there. I just expressed x equal to some p/q. But as you can see, p and q has common factors. So you need to cancel and come to a point, where p and q can't be cancelled any further

  36. 2bornot2b
    • 5 years ago
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    Take a look at page 14 (example 5) of this book http://books.google.co.in/books?id=SnvBeodeTDcC&printsec=frontcover&source=gbs_ge_summary_r&cad=0#v=onepage&q&f=false

  37. 2bornot2b
    • 5 years ago
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    A similar problem is solved there

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