anonymous
  • anonymous
Solve the problem.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[6\overline{.25}= P/Q\]
2bornot2b
  • 2bornot2b
Do you want to express 6.25252525..........as P/Q, where P and Q are coprimes?
anonymous
  • anonymous
yes i do want to express it like that... and it just shows it like that on my paper p/q as a fraction.

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2bornot2b
  • 2bornot2b
First I say let x = 6.252525........... Now I multiply both sides by 10^4
2bornot2b
  • 2bornot2b
(10^4)x=62525.2525...
anonymous
  • anonymous
On my homework it says to multiply it by a hundred or that is what my teacher told me.
2bornot2b
  • 2bornot2b
You may do that, it doesn't matter
2bornot2b
  • 2bornot2b
Say at first you multiply by 100, then multiply by 10 In my problem I am first multiplying by 10000, and then by 1000
anonymous
  • anonymous
Oh well i am not sure how that is why i posted it on here haha.
2bornot2b
  • 2bornot2b
what do you mean by "Oh well i am not sure how that is"
2bornot2b
  • 2bornot2b
Any way, since I see you are already familiar with the procedure. I am stating it once again, in a better way, so that you understand the thing better.
anonymous
  • anonymous
I am not sure how to multiply it by a 100 like i don't know how to solve it.
2bornot2b
  • 2bornot2b
STEP 1. Assume x = (the number given to you)
2bornot2b
  • 2bornot2b
STEP 2. Multiply both sides by 10^n
2bornot2b
  • 2bornot2b
STEP 3: Multiply both sides by 10^m
2bornot2b
  • 2bornot2b
So now you have two equations (Not m must be lesser than n)
2bornot2b
  • 2bornot2b
Subtract the second equation from the first
2bornot2b
  • 2bornot2b
Now you will get a good equation which looks like P/Q
2bornot2b
  • 2bornot2b
I am solving the problem given by you....
anonymous
  • anonymous
yes i know.
2bornot2b
  • 2bornot2b
|dw:1327088110491:dw|
anonymous
  • anonymous
now what do i do after this doesnt it have to be turned into an equation.
2bornot2b
  • 2bornot2b
|dw:1327088136907:dw|
2bornot2b
  • 2bornot2b
|dw:1327088233575:dw|
2bornot2b
  • 2bornot2b
|dw:1327088285898:dw|
2bornot2b
  • 2bornot2b
|dw:1327088337495:dw|
2bornot2b
  • 2bornot2b
So I have expressed x as P/Q, and x is equal to 6.2525...
2bornot2b
  • 2bornot2b
Did you understand?
anonymous
  • anonymous
So the last part is p/q? And yes for the most part i did.
2bornot2b
  • 2bornot2b
Of course, the last part is p/q
2bornot2b
  • 2bornot2b
However, you must simplify that, to get the actual p and q
anonymous
  • anonymous
alright just making sure... so it does not need to be reduced
2bornot2b
  • 2bornot2b
Yes, you need to reduce ofcourse
anonymous
  • anonymous
alright
2bornot2b
  • 2bornot2b
You can't leave it there. I just expressed x equal to some p/q. But as you can see, p and q has common factors. So you need to cancel and come to a point, where p and q can't be cancelled any further
2bornot2b
  • 2bornot2b
Take a look at page 14 (example 5) of this book http://books.google.co.in/books?id=SnvBeodeTDcC&printsec=frontcover&source=gbs_ge_summary_r&cad=0#v=onepage&q&f=false
2bornot2b
  • 2bornot2b
A similar problem is solved there

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