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anonymous
 4 years ago
A 1,600 kg train car rolling freely on level track at 16 m/s bumps into a 1.0 × 103 kg train car moving at 10.0 m/s in the same direction, and the two latch onto each other and continue together. What is their final speed?
16 m/s
6.0 m/s
10 m/s
14 m/s
anonymous
 4 years ago
A 1,600 kg train car rolling freely on level track at 16 m/s bumps into a 1.0 × 103 kg train car moving at 10.0 m/s in the same direction, and the two latch onto each other and continue together. What is their final speed? 16 m/s 6.0 m/s 10 m/s 14 m/s

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JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0Again, use Conversation of Momentum. The momentum of the two trains before bumping into each other is the same as it is afterwards. Can you write down the momentum before they bump?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0whats the formula again?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thnx....jamesj left me hangin

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0jamesj wants you to try to understand it yourself

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i know but I asked for the formula n he left

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If i knew the formula Id do it on my own...he was helping me...n I appreciate it....jus need more help still

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0total momentum before collision=total momentum after collision

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Correction=the ans is 14m/s not 16 Didn't notice the power '1x103' write it like 1x10^3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea...but I didnt wanna say you were wrong...still helped though :)

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0@physicsme, don't give the answer. Give the formula. Momentum = (mass) x (velocity)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats all i really wated was the formula...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay, actually I was practicing different questions so just wanted to solve it and check the answer.

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0Hence, for example the momentum of the first train before the collision is p1 = m1.v1 = (1600 kg)(16 m/s) = 25,600 kg.m/s The momentum of the second train is p2 = m2.v2 = (103 kg)(10 m/s) = 1,030 kg.m/s [btw, is that mass of the train car right? Looks wrong. If so, fix this calculation] Now after the collision, they have the same velocity v' and their combined mass is m = m1 + m2 Now set the sum of the momentum before = momentum afterwards
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