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virtus Group TitleBest ResponseYou've already chosen the best response.0
\[\ln x \sqrt{x+1} =y\]
 2 years ago

watchmath Group TitleBest ResponseYou've already chosen the best response.0
rewrite first as \(y=\ln(x)+\frac{1}{2}\ln(x+1)\) Therefore \(y'=\frac{1}{x}+\frac{1}{2(x+1)}\)
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
\[\ln (x \sqrt{x+1}) =y\] ?
 2 years ago

BlingBlong Group TitleBest ResponseYou've already chosen the best response.0
Can you restate your question please, I will show you a good way to deal with derivatives well at least that I use. Just split the equation into pieces and derive the pieces then place them all together
 2 years ago

virtus Group TitleBest ResponseYou've already chosen the best response.0
@BlingBlong is it the way watchmath has shown thanks@ watchmath!
 2 years ago
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