## virtus Group Title differentiate log(x(root(x+1)) 2 years ago 2 years ago

1. virtus Group Title

$\ln x \sqrt{x+1} =y$

2. watchmath Group Title

rewrite first as $$y=\ln(x)+\frac{1}{2}\ln(x+1)$$ Therefore $$y'=\frac{1}{x}+\frac{1}{2(x+1)}$$

3. phi Group Title

$\ln (x \sqrt{x+1}) =y$ ?

4. BlingBlong Group Title

Can you restate your question please, I will show you a good way to deal with derivatives well at least that I use. Just split the equation into pieces and derive the pieces then place them all together

5. virtus Group Title

@BlingBlong is it the way watchmath has shown thanks@ watchmath!