Here's the question you clicked on:
virtus
differentiate log(x(root(x+1))
rewrite first as \(y=\ln(x)+\frac{1}{2}\ln(x+1)\) Therefore \(y'=\frac{1}{x}+\frac{1}{2(x+1)}\)
\[\ln (x \sqrt{x+1}) =y\] ?
Can you restate your question please, I will show you a good way to deal with derivatives well at least that I use. Just split the equation into pieces and derive the pieces then place them all together
@BlingBlong is it the way watchmath has shown thanks@ watchmath!