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watchmath
 3 years ago
Best ResponseYou've already chosen the best response.0rewrite first as \(y=\ln(x)+\frac{1}{2}\ln(x+1)\) Therefore \(y'=\frac{1}{x}+\frac{1}{2(x+1)}\)

phi
 3 years ago
Best ResponseYou've already chosen the best response.1\[\ln (x \sqrt{x+1}) =y\] ?

BlingBlong
 3 years ago
Best ResponseYou've already chosen the best response.0Can you restate your question please, I will show you a good way to deal with derivatives well at least that I use. Just split the equation into pieces and derive the pieces then place them all together

virtus
 3 years ago
Best ResponseYou've already chosen the best response.0@BlingBlong is it the way watchmath has shown thanks@ watchmath!
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