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virtus

  • 4 years ago

differentiate log(x(root(x+1))

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  1. virtus
    • 4 years ago
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    \[\ln x \sqrt{x+1} =y\]

  2. watchmath
    • 4 years ago
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    rewrite first as \(y=\ln(x)+\frac{1}{2}\ln(x+1)\) Therefore \(y'=\frac{1}{x}+\frac{1}{2(x+1)}\)

  3. phi
    • 4 years ago
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    \[\ln (x \sqrt{x+1}) =y\] ?

  4. BlingBlong
    • 4 years ago
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    Can you restate your question please, I will show you a good way to deal with derivatives well at least that I use. Just split the equation into pieces and derive the pieces then place them all together

  5. virtus
    • 4 years ago
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    @BlingBlong is it the way watchmath has shown thanks@ watchmath!

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