Here's the question you clicked on:
BlingBlong
Solve cos^(2)(x) - 3sin(x) = 3 for x on [0, 2pi] So I have simplified the function down to (-sin(x) - 2)(sin(x) + 1) = 0 or (-sin(x) -1)(sin(x) + 2) = 0 I have determined x = 3pi/2 as sin(3pi/2) = 1/2 Is that the only value possible As I don't think there is a value in the domain of this function that I could use to solve (sin(x) + 2) or (-sin(x) - 2) I could imput arcsin(2) but would that be wrong and if so why?
because the value of sin is at most 1. SO arcsin(2) is undefined. So the solutions only comes from -sin x -1 =0
made a typo. so I'm correct.
yes \(e\pi/2\) is the only answer
so I should always adhere to the range of the unit circle when dealing with trig functions?
yeah I was wondering lol