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BlingBlong
Group Title
Solve cos^(2)(x)  3sin(x) = 3 for x on [0, 2pi]
So I have simplified the function down to
(sin(x)  2)(sin(x) + 1) = 0
or
(sin(x) 1)(sin(x) + 2) = 0
I have determined x = 3pi/2 as sin(3pi/2) = 1/2
Is that the only value possible As I don't think there is a value in the domain of this function that I could use to solve
(sin(x) + 2)
or
(sin(x)  2)
I could imput arcsin(2) but would that be wrong and if so why?
 2 years ago
 2 years ago
BlingBlong Group Title
Solve cos^(2)(x)  3sin(x) = 3 for x on [0, 2pi] So I have simplified the function down to (sin(x)  2)(sin(x) + 1) = 0 or (sin(x) 1)(sin(x) + 2) = 0 I have determined x = 3pi/2 as sin(3pi/2) = 1/2 Is that the only value possible As I don't think there is a value in the domain of this function that I could use to solve (sin(x) + 2) or (sin(x)  2) I could imput arcsin(2) but would that be wrong and if so why?
 2 years ago
 2 years ago

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watchmath Group TitleBest ResponseYou've already chosen the best response.1
because the value of sin is at most 1. SO arcsin(2) is undefined. So the solutions only comes from sin x 1 =0
 2 years ago

BlingBlong Group TitleBest ResponseYou've already chosen the best response.0
sin(3pi/2) = 1
 2 years ago

BlingBlong Group TitleBest ResponseYou've already chosen the best response.0
made a typo. so I'm correct.
 2 years ago

watchmath Group TitleBest ResponseYou've already chosen the best response.1
yes \(e\pi/2\) is the only answer
 2 years ago

BlingBlong Group TitleBest ResponseYou've already chosen the best response.0
so I should always adhere to the range of the unit circle when dealing with trig functions?
 2 years ago

watchmath Group TitleBest ResponseYou've already chosen the best response.1
I mean \(3\pi/2\)
 2 years ago

BlingBlong Group TitleBest ResponseYou've already chosen the best response.0
yeah I was wondering lol
 2 years ago
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