anonymous
  • anonymous
Solve cos^(2)(x) - 3sin(x) = 3 for x on [0, 2pi] So I have simplified the function down to (-sin(x) - 2)(sin(x) + 1) = 0 or (-sin(x) -1)(sin(x) + 2) = 0 I have determined x = 3pi/2 as sin(3pi/2) = 1/2 Is that the only value possible As I don't think there is a value in the domain of this function that I could use to solve (sin(x) + 2) or (-sin(x) - 2) I could imput arcsin(2) but would that be wrong and if so why?
Mathematics
chestercat
  • chestercat
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watchmath
  • watchmath
because the value of sin is at most 1. SO arcsin(2) is undefined. So the solutions only comes from -sin x -1 =0
anonymous
  • anonymous
sin(3pi/2) = -1
anonymous
  • anonymous
made a typo. so I'm correct.

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watchmath
  • watchmath
yes \(e\pi/2\) is the only answer
anonymous
  • anonymous
so I should always adhere to the range of the unit circle when dealing with trig functions?
watchmath
  • watchmath
I mean \(3\pi/2\)
anonymous
  • anonymous
yeah I was wondering lol

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