A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Solve cos^(2)(x)  3sin(x) = 3 for x on [0, 2pi]
So I have simplified the function down to
(sin(x)  2)(sin(x) + 1) = 0
or
(sin(x) 1)(sin(x) + 2) = 0
I have determined x = 3pi/2 as sin(3pi/2) = 1/2
Is that the only value possible As I don't think there is a value in the domain of this function that I could use to solve
(sin(x) + 2)
or
(sin(x)  2)
I could imput arcsin(2) but would that be wrong and if so why?
anonymous
 4 years ago
Solve cos^(2)(x)  3sin(x) = 3 for x on [0, 2pi] So I have simplified the function down to (sin(x)  2)(sin(x) + 1) = 0 or (sin(x) 1)(sin(x) + 2) = 0 I have determined x = 3pi/2 as sin(3pi/2) = 1/2 Is that the only value possible As I don't think there is a value in the domain of this function that I could use to solve (sin(x) + 2) or (sin(x)  2) I could imput arcsin(2) but would that be wrong and if so why?

This Question is Closed

watchmath
 4 years ago
Best ResponseYou've already chosen the best response.1because the value of sin is at most 1. SO arcsin(2) is undefined. So the solutions only comes from sin x 1 =0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0made a typo. so I'm correct.

watchmath
 4 years ago
Best ResponseYou've already chosen the best response.1yes \(e\pi/2\) is the only answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so I should always adhere to the range of the unit circle when dealing with trig functions?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah I was wondering lol
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.