if two equal chords AB and CD meet at point P when extended, prove that the secant segment AP and CP are equal
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This is the picture i have for the question
hhmmm - i'm searching my memory with this one.
if we can show that AC is parallel to BD then we can use similar triangles
yeah - thats basically the same as mine
Thanks i thought so...
i'm pretty sure they are parallel but not sure why!
Im not sure why as well thankf for the help
To Prove this you need to show that angle A = angle C
since the chords are equal, arc AB = arc CD
angle A = arc BC/2
angle C = arc AD/2
arc BC = arc CD + arc BD
arc AD = arc AB + arc BD
using substitution you can show that:
arc BC = arc AD, therefore showing that angle A = angle C