anonymous
  • anonymous
How many solutions exist for the system, x + y = 1 and y = -x + 1? A. no solution B. one solution C. infinitely many solutions
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

JamesJ
  • JamesJ
Notice that the two equations are identical because y = -x + 1 <=> y + x = x - x + 1 = 1 Hence you only have one equation x + y =1. How many solutions are there to that equation?
anonymous
  • anonymous
1?
JamesJ
  • JamesJ
Well, x =1, y = 0 is one solution x = 2, y = -1 is another solution So is x = 0, y =1 In fact, if you drew the graph of that equation, there would be an infinite number of points on it, reflecting the fact there are an infinite number of answers.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
ok thanks :)
JamesJ
  • JamesJ
In general, if you have two variables you need two equations to have a unique solution. With two variables and one equation, there are an infinite number of solutions.

Looking for something else?

Not the answer you are looking for? Search for more explanations.