- anonymous

Which equation has this graph?

- katieb

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- anonymous

##### 1 Attachment

- anonymous

Answer choices available:
A. y = x2 - 6x + 5
B. y = -x2 - 6x + 5
C. y = -x2 - 6x - 5
D. y = x2 + 6x - 5

- heisenberg

You said you tried plugging in some points from the graph in these equations? What points did you choose?

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## More answers

- anonymous

Oh that was for a different equation. This one is a new one.

- heisenberg

Ah, well same method should work. There are two points that are very easy to spot here: the "zeros" of the graph: (1,0) and (5,0)
do you see that?

- anonymous

Not exactly.. :/ I don't get this one.

- heisenberg

So can you tell me any point on that graph? A point is an x and y coordinate.

- anonymous

1 and 3? I don't know. :(

- heisenberg

A point looks like this: (x, y).
These numbers correspond to points on graphs. Do you see how (1,0) lies on that graph? Do you see how (0,0) does not?

- anonymous

Yeah I suppose.

- heisenberg

|dw:1327095609111:dw|
like that^

- anonymous

Alright, then what's next?

- heisenberg

The graph "passes through" (1,0) but not (0,0)

- heisenberg

So we know (1,0) is a point on this graph. So let's try and plug x = 1 and y = 0 into those 4 choices and see which one works.

- heisenberg

A. y = x2 - 6x + 5
B. y = -x2 - 6x + 5
C. y = -x2 - 6x - 5
D. y = x2 + 6x - 5
Can you plug x = 1 and y = 0 into any of these?

- heisenberg

I'll do the first one for you:
y = x^2 - 6x + 5
if x = 1, and y = 0 we get:
0 = (1)^2 - 6(1) + 5
0 = 1 - 6 + 5
0 = -5 + 5
0 = 0
So this is true for equation A. Equation A is a possible answer.

- heisenberg

Are you stuck/confused?

- anonymous

Hold on I'm trying to figure them out.

- heisenberg

!!! Nice :)

- anonymous

For the B, I solved the equation and got the answer 6. Where do I go from there for B?

- heisenberg

You should have gotten an equation for equation B: something like:
? = ?

- heisenberg

not just a single number, but an equation.

- anonymous

Well I'm saying where do I go after I solve for that? To get to ?=?

- heisenberg

So let's take a look at B:
y = - x^2 - 6x + 5
if x = 1, y = 0, plug them in the equation:
0 = - (1^2) - 6(1) + 5
0 = -1 - 6 + 5
0 = -2
but this is not true! 0 does not equal -2, do you agree?

- anonymous

I agree! So basically, once I have plugged in everything, I get rid of the x's and just put those together and I will find out what 0 equals?

- anonymous

A will be my answer because that is the only one that equals 0!

- heisenberg

You want to find the equation where the points (x=1,y=0) and also (x=5,y=0) satisfy the equation.

- heisenberg

I think A is right as well!

- anonymous

Thank you heisenberg! :)

- heisenberg

Np :). Hope you understood it a little bit.
Basically, this was our process:
1. Find a point that lies on the graph
2. Check each equation to see if this point's x and y result in a *true* equation.
Good luck :)

- anonymous

Thanks!! :)

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