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alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0Answer choices available: A. y = x2  6x + 5 B. y = x2  6x + 5 C. y = x2  6x  5 D. y = x2 + 6x  5

heisenberg
 3 years ago
Best ResponseYou've already chosen the best response.3You said you tried plugging in some points from the graph in these equations? What points did you choose?

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0Oh that was for a different equation. This one is a new one.

heisenberg
 3 years ago
Best ResponseYou've already chosen the best response.3Ah, well same method should work. There are two points that are very easy to spot here: the "zeros" of the graph: (1,0) and (5,0) do you see that?

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0Not exactly.. :/ I don't get this one.

heisenberg
 3 years ago
Best ResponseYou've already chosen the best response.3So can you tell me any point on that graph? A point is an x and y coordinate.

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.01 and 3? I don't know. :(

heisenberg
 3 years ago
Best ResponseYou've already chosen the best response.3A point looks like this: (x, y). These numbers correspond to points on graphs. Do you see how (1,0) lies on that graph? Do you see how (0,0) does not?

heisenberg
 3 years ago
Best ResponseYou've already chosen the best response.3dw:1327095609111:dw like that^

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0Alright, then what's next?

heisenberg
 3 years ago
Best ResponseYou've already chosen the best response.3The graph "passes through" (1,0) but not (0,0)

heisenberg
 3 years ago
Best ResponseYou've already chosen the best response.3So we know (1,0) is a point on this graph. So let's try and plug x = 1 and y = 0 into those 4 choices and see which one works.

heisenberg
 3 years ago
Best ResponseYou've already chosen the best response.3A. y = x2  6x + 5 B. y = x2  6x + 5 C. y = x2  6x  5 D. y = x2 + 6x  5 Can you plug x = 1 and y = 0 into any of these?

heisenberg
 3 years ago
Best ResponseYou've already chosen the best response.3I'll do the first one for you: y = x^2  6x + 5 if x = 1, and y = 0 we get: 0 = (1)^2  6(1) + 5 0 = 1  6 + 5 0 = 5 + 5 0 = 0 So this is true for equation A. Equation A is a possible answer.

heisenberg
 3 years ago
Best ResponseYou've already chosen the best response.3Are you stuck/confused?

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0Hold on I'm trying to figure them out.

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0For the B, I solved the equation and got the answer 6. Where do I go from there for B?

heisenberg
 3 years ago
Best ResponseYou've already chosen the best response.3You should have gotten an equation for equation B: something like: ? = ?

heisenberg
 3 years ago
Best ResponseYou've already chosen the best response.3not just a single number, but an equation.

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0Well I'm saying where do I go after I solve for that? To get to ?=?

heisenberg
 3 years ago
Best ResponseYou've already chosen the best response.3So let's take a look at B: y =  x^2  6x + 5 if x = 1, y = 0, plug them in the equation: 0 =  (1^2)  6(1) + 5 0 = 1  6 + 5 0 = 2 but this is not true! 0 does not equal 2, do you agree?

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0I agree! So basically, once I have plugged in everything, I get rid of the x's and just put those together and I will find out what 0 equals?

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0A will be my answer because that is the only one that equals 0!

heisenberg
 3 years ago
Best ResponseYou've already chosen the best response.3You want to find the equation where the points (x=1,y=0) and also (x=5,y=0) satisfy the equation.

heisenberg
 3 years ago
Best ResponseYou've already chosen the best response.3I think A is right as well!

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0Thank you heisenberg! :)

heisenberg
 3 years ago
Best ResponseYou've already chosen the best response.3Np :). Hope you understood it a little bit. Basically, this was our process: 1. Find a point that lies on the graph 2. Check each equation to see if this point's x and y result in a *true* equation. Good luck :)
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