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Well, not by the -18, but it could indirectly help the 65 make f(k) prime.

It looks like zero primes

the answer is 0 but i dont understand how you arrived at that

k^2 - 18 k + 65 = (k-5)(k-13)

Yes, because after the multiplication, that product would be divisible by both x and y

so x=(k-5) and y= (k-13)

x*y is composite unless....
(k-5)*(k-13) is composite unless....

I was getting nervous, cause I do not know how to say it any other way