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anonymous
 4 years ago
12^11 = 2^x
How can I use log to solve this problem?
anonymous
 4 years ago
12^11 = 2^x How can I use log to solve this problem?

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asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1Sorry the site went down and I lost everything I typed. let me try again...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sad face. Thanks for the effort though

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1If you have:\[a^b=c^d\]Then you can take logs of both sides to get:\[\log(a^b)=\log(c^d)\]\[\therefore b\log(a)=d\log(c)\]You should be able to use this to solve your problem.

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1Let me know f you need more help and/or explanation.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what does the 3 dots mean before blog?

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1\(\therefore\) mean "therefore"

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay, let me see if i can get it now, just a sec

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is the answer 39.5 approximately?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks, but i need to ask you something

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the original question is the product of 12^11 x 18^13 = 2^p x 3^q, and it wants me to find 4q  3p, and all of the possible answers are integers.

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1ok  interesting problem  it me think a bit...

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1ok  I think the best approach is try and replace the 12 and 18 by their prime factors.\[12=2^2*3\]\[18=2*3^2\]

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1can you "see" how to solve it then?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02^2 x 3 x 2 x 3^2 = 2^3 x 3^3! Then you multiply by 11 and 13 respectively and get p = 33 and q = 39, 4 x 39  3 x 33 = 57 which isnt a possible answer. :(, did i mess up somewhere?

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1not quite  let me take you through it stepbystep...

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1\[12^{11}=(12)^{11}=(2^2*3)^{11}=2^{22}*3^{11}\]use same technique with 18 and then see what you get.

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1I used the rule:\[(x^a)^b=x^{ab}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohh, forgot about that; p = 35, q = 37? So the answer is... 43, and its a possible answer! Yay

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1well done  you are a fast learning!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks. You are a good teacher.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0United Kingdom? What's it like there?
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