anonymous
  • anonymous
12^11 = 2^x How can I use log to solve this problem?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
asnaseer
  • asnaseer
Sorry the site went down and I lost everything I typed. let me try again...
anonymous
  • anonymous
Sad face. Thanks for the effort though
asnaseer
  • asnaseer
If you have:\[a^b=c^d\]Then you can take logs of both sides to get:\[\log(a^b)=\log(c^d)\]\[\therefore b\log(a)=d\log(c)\]You should be able to use this to solve your problem.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

asnaseer
  • asnaseer
Let me know f you need more help and/or explanation.
anonymous
  • anonymous
what does the 3 dots mean before blog?
asnaseer
  • asnaseer
\(\therefore\) mean "therefore"
anonymous
  • anonymous
okay, let me see if i can get it now, just a sec
anonymous
  • anonymous
is the answer 39.5 approximately?
asnaseer
  • asnaseer
perfect! - well done
anonymous
  • anonymous
thanks, but i need to ask you something
asnaseer
  • asnaseer
go ahead...
anonymous
  • anonymous
the original question is the product of 12^11 x 18^13 = 2^p x 3^q, and it wants me to find 4q - 3p, and all of the possible answers are integers.
asnaseer
  • asnaseer
ok - interesting problem - it me think a bit...
asnaseer
  • asnaseer
ok - I think the best approach is try and replace the 12 and 18 by their prime factors.\[12=2^2*3\]\[18=2*3^2\]
asnaseer
  • asnaseer
can you "see" how to solve it then?
anonymous
  • anonymous
2^2 x 3 x 2 x 3^2 = 2^3 x 3^3! Then you multiply by 11 and 13 respectively and get p = 33 and q = 39, 4 x 39 - 3 x 33 = 57 which isnt a possible answer. :(, did i mess up somewhere?
asnaseer
  • asnaseer
not quite - let me take you through it step-by-step...
anonymous
  • anonymous
thanks
asnaseer
  • asnaseer
\[12^{11}=(12)^{11}=(2^2*3)^{11}=2^{22}*3^{11}\]use same technique with 18 and then see what you get.
asnaseer
  • asnaseer
I used the rule:\[(x^a)^b=x^{ab}\]
anonymous
  • anonymous
ohh, forgot about that; p = 35, q = 37? So the answer is... 43, and its a possible answer! Yay
asnaseer
  • asnaseer
well done - you are a fast learning!
asnaseer
  • asnaseer
*learner
anonymous
  • anonymous
Thanks. You are a good teacher.
asnaseer
  • asnaseer
:) Thanks
anonymous
  • anonymous
United Kingdom? What's it like there?

Looking for something else?

Not the answer you are looking for? Search for more explanations.