Anyone online?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

Q4
1 Attachment
Let me sketch out a FBD for you really quick.
Derp heh. A diagram, not a free body diagram. No forces here :p

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

It is dealing with v = u + at first, then s = ut + 0.5at^2
|dw:1327119231882:dw| First move is finding when A is at its apex.
i got 0.5 secs
You can find that by solving \(v = v_0 + at\) for t, and plugging in \(v_0 = 5\) and \(v = 0\) (since velocity is 0 at the apex), and \(-9.8ms^{-2}\) for a, since we are accelerating against gravity.
If you got 0.5s, I assume you're using \(-10ms^{-2}) as an approximate for gravity?
Check this out..
1 Attachment
I get 2.775 (= 2.8) for the s of B...
You seem to be using 7 for its velocity, it has a v_0 of 8.
OMG! im blind.
:) It happens. The other s is right, so I'm guessing everything else will work out :)
i get correct answer now, w.r.t marking scheme! :D 1.5N.
!! Awesome :)
Yes!
Just watch out for those numbers :) They're sneaky little things.
Thanks!!! ^_^
No problem!
what about the (ii) part?
Whoops, let me have a look-see.
Is it part ii you want to see?
Yes.
I'll let mathmate help heh. I got distracted trying to track down a song that's been stuck in my head all day >_<
I have 8t-(g/2)t^2-(5t-(g/2)t^2) = 0.9 which solves for 3t=0.9, or t=0.3 (the g... terms cancel out). Then height of A is 5(0.3)-(g/2)(0.3)^2 =1.0586 (using g=9.81)
OMG! that's correct. :D
http://www.xtremepapers.com/CIE/International%20A%20And%20AS%20Level/9709%20-%20Mathematics/9709_w02_ms_4.pdf Page 4.
i was confused about which one to make variable to.. hehe it was "t"/
Great, I guess I got too many digits, but it's easier to cut than to add! :)
right.
thanks!
Good night then... till next time!
You're welcome! :)
:]

Not the answer you are looking for?

Search for more explanations.

Ask your own question