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saifoo.khan
 4 years ago
Anyone online?
saifoo.khan
 4 years ago
Anyone online?

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shadowfiend
 4 years ago
Best ResponseYou've already chosen the best response.3Let me sketch out a FBD for you really quick.

shadowfiend
 4 years ago
Best ResponseYou've already chosen the best response.3Derp heh. A diagram, not a free body diagram. No forces here :p

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.1It is dealing with v = u + at first, then s = ut + 0.5at^2

shadowfiend
 4 years ago
Best ResponseYou've already chosen the best response.3dw:1327119231882:dw First move is finding when A is at its apex.

shadowfiend
 4 years ago
Best ResponseYou've already chosen the best response.3You can find that by solving \(v = v_0 + at\) for t, and plugging in \(v_0 = 5\) and \(v = 0\) (since velocity is 0 at the apex), and \(9.8ms^{2}\) for a, since we are accelerating against gravity.

shadowfiend
 4 years ago
Best ResponseYou've already chosen the best response.3If you got 0.5s, I assume you're using \(10ms^{2}) as an approximate for gravity?

shadowfiend
 4 years ago
Best ResponseYou've already chosen the best response.3I get 2.775 (= 2.8) for the s of B...

shadowfiend
 4 years ago
Best ResponseYou've already chosen the best response.3You seem to be using 7 for its velocity, it has a v_0 of 8.

shadowfiend
 4 years ago
Best ResponseYou've already chosen the best response.3:) It happens. The other s is right, so I'm guessing everything else will work out :)

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.1i get correct answer now, w.r.t marking scheme! :D 1.5N.

shadowfiend
 4 years ago
Best ResponseYou've already chosen the best response.3Just watch out for those numbers :) They're sneaky little things.

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.1what about the (ii) part?

shadowfiend
 4 years ago
Best ResponseYou've already chosen the best response.3Whoops, let me have a looksee.

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1Is it part ii you want to see?

shadowfiend
 4 years ago
Best ResponseYou've already chosen the best response.3I'll let mathmate help heh. I got distracted trying to track down a song that's been stuck in my head all day >_<

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1I have 8t(g/2)t^2(5t(g/2)t^2) = 0.9 which solves for 3t=0.9, or t=0.3 (the g... terms cancel out). Then height of A is 5(0.3)(g/2)(0.3)^2 =1.0586 (using g=9.81)

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.1OMG! that's correct. :D

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.1i was confused about which one to make variable to.. hehe it was "t"/

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1Great, I guess I got too many digits, but it's easier to cut than to add! :)

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1Good night then... till next time!
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