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True
speed = distance/time *time = distance

umm
is this a physics question?

No, this is Math,

okies :)

Now it's fine.
:D

Okay!! (:
can u solve the question in the picture?

No worries. Thanks for trying! :)

sorries me cant do it either
:(

np

um its just at
constant speed
not instantaneous right?

first it has increasing speed, then constant speed,
i want to draw the distance-time graph for this.

could you wait a bit
ill try to help
this stuff is in my physics book

its the math it uses

This might help,

the formula you just use is a regular d=r/t

idk. this is the screenshot form the marking scheme.. i have no idea how they did that.

formula for aceleration
final speed= initial speed + speed change

\[a = \frac{v-u}{t}\]Right?

But how we will draw the speed-time? :l

on you graph
y is the speed
x is the time

wait. sorry..
that is already drawn in the question.. i want displacement time. hehe,

displacement ?
umm i dont understand
displacement from what?

it is cut off

can you type the rest it?

then you may probably use
d=rt
to figure out the rest of the stuff
i think this is how it is done
:\