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anonymous

  • 4 years ago

simplify : x^2(y^2*z^3)^-2/y^3(xz^-3)^2

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  1. anonymous
    • 4 years ago
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    um...... Wait

  2. Diyadiya
    • 4 years ago
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    \[\huge \frac{x^2y^{-4}z^-{6}}{y^3x^2z^{-6}}\] Can you do now ?

  3. anonymous
    • 4 years ago
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    Actually, no . It's so confusing.

  4. anonymous
    • 4 years ago
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    How did you do the last result please ?

  5. Diyadiya
    • 4 years ago
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    Remember :\[\huge x^m \times x^n = x^{m+n}\]\[\huge x^{-m}= \frac{1}{x^m}\]

  6. Diyadiya
    • 4 years ago
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    \[\huge \frac{x^2(y^2*z^3)^{-2}}{y^3(xz^{-3})^2}=\frac{x^2 (y^2)^{-2}(z^3)^{-2}}{y^3(x)^2(z^{-3})^2}\]

  7. anonymous
    • 4 years ago
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    I have to say " thank you a lot Diyadiya "

  8. Diyadiya
    • 4 years ago
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    You still have to simplify it You're Welcome (:

  9. anonymous
    • 4 years ago
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    atleast give her medals!!!

  10. anonymous
    • 4 years ago
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    Where are you ? I need your help again .

  11. anonymous
    • 4 years ago
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    Sorry " I forgot to click on Good answer "

  12. Diyadiya
    • 4 years ago
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    No problem your other question has been answered by ishaan :)

  13. anonymous
    • 4 years ago
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    but it's not clear answer .

  14. Diyadiya
    • 4 years ago
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    ok wait

  15. Diyadiya
    • 4 years ago
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    sorry i gtg now ask in the chat for someone to help you out :)

  16. anonymous
    • 4 years ago
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    okay .

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