1. anonymous

Is it like this?$\frac{dy}{dx} = 1 + 2 \frac{x^2}{x \cos y}$

2. anonymous

no, it's like this: dy/dx= (1+2x^2)/(x cos y)

3. anonymous

Oh

4. anonymous

$\frac{dy}{dx} = \frac{1+2x^2}{x \cos y}$ $\cos y dy = \frac{1}{x}dx + 2x dx$

5. anonymous

Integrate it now! :-D

6. anonymous

I am not a Greedy kid (Or, at least I believe so) but if you'd be kind enough to award me a medal for my work (at least for the LaTeX), I will definitely level up soon.

7. anonymous

Hahah, I will but how ?

8. anonymous

Oh, I see. Just click on Good Answer

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