anonymous
  • anonymous
What about this dy/dx= 1+2x^2/x cos y
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
Is it like this?\[\frac{dy}{dx} = 1 + 2 \frac{x^2}{x \cos y}\]
anonymous
  • anonymous
no, it's like this: dy/dx= (1+2x^2)/(x cos y)
anonymous
  • anonymous
Oh

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anonymous
  • anonymous
\[\frac{dy}{dx} = \frac{1+2x^2}{x \cos y}\] \[ \cos y dy = \frac{1}{x}dx + 2x dx\]
anonymous
  • anonymous
Integrate it now! :-D
anonymous
  • anonymous
I am not a Greedy kid (Or, at least I believe so) but if you'd be kind enough to award me a medal for my work (at least for the LaTeX), I will definitely level up soon.
anonymous
  • anonymous
Hahah, I will but how ?
anonymous
  • anonymous
Oh, I see. Just click on Good Answer

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